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2 years ago

HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!

2 answers:

8 0

Hello! Sorry this is a little late!

The answer to your question would best be option C, y<span>es, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

I just took this test, and can 100% confirm this is the correct answer!

Hope this helps, and have a great day! :)</span>

valkas [14]2 years ago

3 0

Answer:

c. Yes, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

Explanation:

As we know by Coulomb's law the force of attraction or force of repulsion between two charged bodies is given by

$F = \frac{kQ_1Q_2}{r^2}$

now we know that

if two charges are of same sign then they will repel each other and if the two charges are of opposite sign then they must attract each other.

So here since two balloons are of negative charge so we can say that electric field on one balloon will repel the charge of other balloon.

So here both balloons will repel each other and correct answer will be

c. Yes, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

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11.8 m/s

Explanation:

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2 years ago

A resistor and an inductor are connected in series to a battery. The battery is suddenly removed from the circuit. The time cons

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3 years ago

Read 2 more answers

A capacitor C is fully charged by connecting it to battery of V Volt. Then it is disconnected from battery. If the separation be

vodomira [7]

Answer:

Explanation:

i )

When it is disconnected with the battery , the charge stored in it becomes fixed . When the plate distance becomes half , its capacitance becomes twice from C to 2C . Let charge stored in it at the time of disconnection from battery be Q . Let plate separation reduces from d to d / 2

So charged stored in it will remain unchanged .

ii )

Potential difference = charge / capacitance

in the first case potential difference = Q / C

in the second case potential difference = Q / 2C

So potential difference becomes half .

iii ) electric field = potential diff / plate separation

in the first case electric field = Q / (d x C )

in the second case electric field = 2 Q / (d x 2C)

= Q / (d x C )

So electric field remains unchanged .

iv)

energy stored in first case = Q² / 2C

In the second case energy stored = Q² / 2x2C

so energy stored becomes half .

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3 years ago

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2 years ago

Look at the velocity versus time graph below. What is the magnitude of the displacement of the object after it travels for three

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Answer:

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2 years ago

HELP ASAP﻿﻿!!!!! ﻿ILL MARK YOU BRAINLIEST!

HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!