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ollegr [7]
3 years ago
13

According to le chatelier's principle, increasing the pressure of the system shown below will shift equilibrium to the left (tow

ards reactants).n2 (
g. + 3h2 (
g. 2nh3 (
g.
Chemistry
1 answer:
jasenka [17]3 years ago
4 0
N2(g) + 3H2(g) =2NH3(g)

Number of moles of reactants > product...
Therfore if pressure is increased.
Equilibrium is disturbed according to LCP....
Equilibrium shift to the right (product)
......
If you want to understant the fundamental concept:

Take for example 2A + 3B = 4C
Reactant: 5 moles (5 volumes)
Product: 4 moles (4 volumes)

When pressure of a gas is increased, volume decreases!
(Vice-versa)

If pressure is increased, volume decreases. Hence number of collisions INCREASES(constrain). Equilibrium shifts in such a direction so as to decrease the number of collision accordinf to LCP...
This happens when number of paeticles decreases as equilibrium shift forward because the forward reaction is accompanied by a decrease in number of particles (5 to 4)
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How many moles of Carbon are in 3.06 g of Carbon
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Answer:

\boxed {\boxed {\sf 0.255 \ mol \ C }}

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

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Set up a ratio using the molar mass.

\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Since we are converting 3.06 grams to moles, we multiply by that value.

3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}                      

3.06 * \frac{1 \ mol \ C}{12.011 }    

\frac {3.06}{12.011 } \ mol \ C                                

0.25476646 \ mol \ C

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

  • 0.25476646

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

0.255 \ mol \ C

3.06 grams of carbon is approximately <u>0.255 moles of carbon.</u>

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