Iodate has a charge of -1, this means its chemical symbol
must be IO3(-1) while Lanthanum is La(+3). Therefore making the compound
La(IO3)3.
However sulfate has a chemical symbol of SO4(-2), it has
charge of -2, therefore the formula for lanthanum sulfate is:
<span>La2(SO4)<span>3</span></span>
Answer:
There are 5 neutrons in beryllium
Answer: The concentration of KOH for the final solution is 0.275 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,
n = moles of solute
= volume of solution in ml = 150 ml
moles of solute =
Now put all the given values in the formula of molality, we get

According to the dilution law,

where,
= molarity of stock solution = 1.19 M
= volume of stock solution = 15.0 ml
= molarity of diluted solution = ?
= volume of diluted solution = 65.0 ml
Putting in the values we get:


Therefore, the concentration of KOH for the final solution is 0.275 M