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yan [13]
3 years ago
15

Explain how a graphical analysis can be used to explore the relationship between any two scientific variables.

Chemistry
1 answer:
noname [10]3 years ago
4 0

A graphical analysis can be used to explore the relationship between any two scientific variables by showing numerical data through a graph, which is an easier and more vivid way to interpret results, compared to reading a table of numbers.

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Which branch science consist of?<br>​
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Modern science is typically divided into three major branches that consist of the natural sciences (biology, chemistry, physics, astronomy and Earth science), which study nature in the broadest sense; the social sciences (e.g. psychology, sociology, economics, history) which study people and societies; and the formal ...

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Which power source uses the earth’s internal heat?
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Answer:

Its geothermal energy.

Explanation:

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5 0
3 years ago
18. What is the percent by mass sugar of a solution made by dissolving 12.45 grams of sugar in 100 grams of water?
Fantom [35]

The percent by mass sugar of a solution : 11.07%

<h3>Further explanation</h3>

Given

mass of sugar = 12.45 g

mass of water = 100 g

Required

The percent by mass

Solution

Mass of solution :

\tt mass~sugar+mass~water=12.45+100=112.45~g

Percent mass of sugar :

\tt \%mass=\dfrac{mass~sugar}{mass~solution}\times 100\%\\\\\%mass=\dfrac{12.45}{112.45}\times 100\%=11.07\%

6 0
3 years ago
For the following unbalanced equation: Cu(s) + AgNO₃(aq) ➞ Cu(NO₃)₂(aq) + Ag(s) if 1.50 moles of copper and 3.00 moles of silver
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7 0
3 years ago
How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?
mash [69]

Answer : Both solutions contain 3.011 X 10^{23} molecules.

Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain 3.011 x 10^{23} molecules.

Avogadro's Number is  N_{A} =  6.022 X 10^{23} which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.

Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.

Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.

Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.

We can calculate the number of molecules for each;

Number of molecules  = N_{A} X M;

∴  Number of molecules =  6.022 X 10^{23} X 0.5 mol/L X 1 L which will be  = 3.011 X 10^{23}

Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.

7 0
3 years ago
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