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yan [13]
3 years ago
15

Explain how a graphical analysis can be used to explore the relationship between any two scientific variables.

Chemistry
1 answer:
noname [10]3 years ago
4 0

A graphical analysis can be used to explore the relationship between any two scientific variables by showing numerical data through a graph, which is an easier and more vivid way to interpret results, compared to reading a table of numbers.

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What are 1,2 and 3 examples of the same periodic table​
Serga [27]

Period

Group

Explanation:

On the periodic table the numbers 1,2 and 3 can represent either groups or periods.

The periodic table gives the arrangement of elements based on their atomic numbers

  • They are divided into vertical columns and horizontal rows
  • The vertical columns are the groups whereas the horizontal rows are the periods.
  • The vertical columns are made up of elements having the same number of electrons in their outermost shell.
  • The horizontal columns are made up of elements having the same number of shell.
  • On the periodic table, the groups are numbered 1 - 18
  • There are 7 periods on the table.

learn more:

Periodic table brainly.com/question/1971327

#learnwithBrainly

5 0
4 years ago
Density is d= m/vol. If a material has a mass of 65.5 g and a volume of 32.5 ml, it has a density of
ryzh [129]

Using the given formula, the density of the material is 2.015 g/mL

<h3>Calculating Density </h3>

From the question, we are to determine the density of the material

From the given formula

Density = Mass / Volume

And from the given information,

Mass = 65.5 g

and volume = 32.5 mL

Putting the parameters into the equation,

Density = 65.5/32.5

Density = 2.015 g/mL

Hence, the density of the material is 2.015 g/mL.

Learn more on Calculating density here: brainly.com/question/24772401

#SPJ1

8 0
2 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

5 0
4 years ago
A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm
Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 ^{\circ}C or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55^{\circ}C = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}

The final temperature is 407.57 K

7 0
3 years ago
‼️ i really need help. if anyone can do 10 pages of a grade 11 chemistry packet (multiple choice) let me know. i can pay money
Alja [10]

Answer:

mmmmmmmmmmmmmmmmmm

Explanation:

6 0
3 years ago
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