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3 years ago

Which of the following elements does not form a diatomic molecule?

Chemistry

1 answer:

gladu [14]3 years ago

6 0

Answer:

Explanation:

Neon is a noble gas, which is monoatomic.

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1.What zodiac sign is October 19,2006? A). Sagittarius B). Libra C). Leo D). Pisces

MrMuchimi

Answer:

B. Libra

Explanation:

Libra's range from September 23rd to October 22nd

5 0

4 years ago

Read 2 more answers

In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows

agasfer [191]

The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
number of empirical units - 1.000
therefore empirical formula = molecular formula
molecular formula - P₂O₅

3 0

3 years ago

True or False

goldenfox [79]

Answer:

I believe its True

4 0

3 years ago

Read 2 more answers

4.85 x 10^-4 tons to cups

fiasKO [112]

Answer:

2.08753919851 cups

0.464942810185139 cups

2.08753919851 cups

Explanation:

i looked it up

7 0

3 years ago

How many atoms are found in 3.45g of CO2?

USPshnik [31]

Answer: The number of carbon and oxygen atoms in the given amount of carbon dioxide is $4.72\times 10^{22}$ and $9.44\times 10^{22}$ respectively

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of carbon dioxide gas = 3.45 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

$\text{Moles of carbon dioxide gas}=\frac{3.45g}{44g/mol}=0.0784mol$

1 mole of carbon dioxide gas contains 1 mole of carbon and 2 moles of oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\time 10^{23}$ number of molecules

So, 0.0784 moles of carbon dioxide gas will contain $1\times 0.0784\times 6.022\times 10^{23}=4.72\times 10^{22}$ number of carbon atoms and $2\times 0.0784\times 6.022\times 10^{23}=9.44\times 10^{22}$ number of oxygen atoms

Hence, the number of carbon and oxygen atoms in the given amount of carbon dioxide is $4.72\times 10^{22}$ and $9.44\times 10^{22}$ respectively

3 0

4 years ago