Answer:
3. crystal habit and cleavage.
Explanation:
Crystal habit is a distinctive characteristic which is shown in its general shape, crystallographic forms, how developed each form is.
Cleavage is the ability of a mineral to break in smooth planes parallel to zones of weak bonding. Cleavage in three directions at right angles (90o). Cubic cleavage. Cleavage in three directions not at right angles (120o and 60o).
Answer:
a) 231.9 °C
b) 100% Sn
c) 327.5 °C
d) 100% Pb
Explanation:
This is a mixture of two solids with different fusion point:
<u>Given that Sn has a lower fusion temperature it will start to melt first at that temperature. </u>
So the first liquid phase forms at 231.9 °C and because Pb starts melting at a higher temperature, that phase's composition will be 100% Sn.
The mixture will be completely melted when you are a the higher melting temperature of all components (in this case Pb), so it will all in liquid phase at 327.5 °C.
At that temperature all Sn was already in liquid state and, therefore, the last solid's composition will be 100% Pb.
Answer:
Ca - 63.546 g
2N - 28.014 g
2O3 - 96 g
Ca(NO3)2 = 187.56 g
187.56 g x 0.75 mol = 140.67 g
Explanation:
Hope this helps
The haze is called smog, hope this helps, pls mark brainliest!
Answer:
There will be 3 peaks.
Relative height of the atomic peaks would be; 158, 160 and 162
Explanation:
We are told that Bromine has two isotopes namely 79Br and 81Br in a 1 : 1 ratio (50 : 50).
This means that a compound which contains 1 bromine atom will have two peaks in the molecular ion region but it depends on which bromine isotope is contained in the molecular ion.
Thus;
Relative height of atomic peaks is given by;
m/z = 79Br¯ 79Br+ = 158
79Br¯ 81Br+ = 160
81Br¯ 81Br+ = 162
