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Papessa [141]
3 years ago
9

Which of the following elements does not form a diatomic molecule?

Chemistry
1 answer:
gladu [14]3 years ago
6 0

Answer:

C

Explanation:

Neon is a noble gas, which is monoatomic.

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EXPLAIN how to identify the reducing agent in a reaction of magnesium with oxygen
Alina [70]

Explanation:

Mg+O>MgO

Here the mg loses it electron and is oxidised and oxygen gains and is reduced.

Mg(2+)and O(2-)

Mg is a reducing agent it makes oxygen to be reduced while itself being oxidised and vice versa.

8 0
3 years ago
NO FILES
MrMuchimi

Answer:

the general equation is: A + X → AX. Where a single compound on the reactant side breaks down into two or more products during a chemical change. The general equation is AX → A + X.

Explanation:

6 0
3 years ago
Calculate the volume of a sample of mercury with a density of 14.6 g/mL and a mass of 1.00 g. The answer is assumed to be in mL.
Darya [45]

Answer:

0.0685 mL

Explanation:

To find the volume of the sample, divide the mass by the density.

(1.00 g)/(14.6 g/mL) = 0.0685 mL

3 0
3 years ago
A 0.55 g sample of H20 contains how many<br>molecules of water?<br>Answer in units of molec.​
noname [10]

Answer:

Explanation:

Num of molecules = num of moles * Avogadro's constant (6.02* 10^23)

But num of moles = reacting mass / molar mass

Molar mass of H20= 2*1 + 16 = 2+16 = 18g

Reacting mass of H20 = 0.55g

Therefore, num of moles of H20 = 0.55g/18g = 0.031 moles

Therefore, num of molecules of H20 = 0.031 * 6.02*10^23

= 1.87*10^22 molecules of H20

7 0
3 years ago
Please help, with step by step work
natali 33 [55]

\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

5 0
2 years ago
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