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Anika [276]
3 years ago
7

Describe the relationship between intrapulmonary pressure, atmospheric pressure, and air flow during normal inspiration and expi

ration, referring to Boyle’s law.
Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
6 0
Boyle’s law= pressure and volume are inversely related. When air flows in Volume increases and pressure decreases, when air flows out the intrapulmonary pressure equilibrates with atmospheric pressure.
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The second messenger cyclic AMP (cAMP) is synthesized from ATP by the activity of the enzyme adenylyl cyclase. Cyclic AMP, in tu
scoundrel [369]

Answer: 1. Cyclic AMP(cAMP) concentration increases;

2. cAMP then binds to the two regulatory subunits;

3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;

4. The catalytic sites are now free to catalyse the various reactions of PKA.

(Note: The question did not list the steps to be placed in the correct order)

Explanation:

The inactive form of Protein Kinase A (PKA) contains two identical sub-units (C) and two identical regulatory sub-units (R). Two auto-inhibitory sequences of the regulatory subunits occupy the catalytic sites of the catalytic subunits. After the reaction of adenylyl cyclase, this inactive form of PKA is activated in the following steps:

1.<em> </em><em>Cyclic AMP</em><em>(</em><em>cAMP</em><em>) concentration increases;</em>

<em>2. </em><em>cAMP</em><em> then binds to the two regulatory subunits;</em>

<em>3. A change in the conformation of enzyme results. The autoinhibitory sequences move away from the active site of the catalytic subunits;</em>

<em>4. The catalytic sites are now free to catalyse the reactions various of </em><em>PKA</em><em> which includes the regulation of glycogen, sugar, and lipid metabolism. </em>

8 0
3 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
Compute the value of the molar heat capacity at constant volume, CVCV, for CO2CO2 on the assumption that there is no vibrational
katovenus [111]

Answer:

Explanation:

Molar heat capacity at constant volume Cv  of a gas = n x .5 R where n is degree of freedom of the gas molecules

CO₂ is a linear molecule , so number of degree of freedom =  3 + 2 = 5

3 is translational and 2 is rotational degree of freedom . There is no vibrational degree of freedom given .

So Cv = 5 / 2 R

= 2.5 R .

4 0
3 years ago
Para el elemento de Z-56 b, que formula minima tiene el compuesto que forma con 17-cl¿ c, que tipo de union hay en dicho compues
inessss [21]

Answer:

ver explicacion

Explanation:

El elemento que tiene el número atómico 56 en la tabla periódica del bario. El bario es un elemento del grupo dos.

Se combina con el cloro para formar cloruro de bario. que tiene la fórmula BaCl2 de acuerdo con la valencia de ambos elementos.

El cloruro de bario es un compuesto iónico.

5 0
3 years ago
After 62.0 min, 33.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics?
nikdorinn [45]
Half life is determined using the equation expressed as:

A = Ao e^-kt

First, we need to find for the value k.

A = .67Ao = Ao e<span>^-k(33 min)
k = 0.0121

The half-life is then calculated as follows:
</span>A = .5Ao = Ao e<span>^-0.0121(t)
</span><span>t = 57.28 min

</span>
3 0
4 years ago
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