All categories

3 years ago

Two show your work questions

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Answer:

x = 1; y = 1; z = 0

Step-by-step explanation:

First problem:

First equation minus second equation: 3y + 2z = 3 Eq. A

Second equation plus third equation: 2y + 4z = 2 Eq. B

-2 times Eq. A plus Eq. B: -4y = -4

y = 1

Substitute y = 1 in Eq. A: 3 + 2z = 3

2z = 0

z = 0

Substitute z = 0 and y = 1 in original first equation:

-2x + 2 + 0 = 0

-2x = -2

x = 1

Answer: x = 1; y = 1; z = 0

You might be interested in

A six-sided dice is thrown once

g100num [7]

A : 1/6 is the answer hope it helps

8 0

3 years ago

Read 2 more answers

The equation c=6.4w represents the cost c for w pounds of walnuts. Does a value of 2.5 for w make sense in this situation? Expla

sineoko [7]

We are given equation: c=6.4w, where the cost c for w pounds of walnuts.

w represents the number of pounds of walnuts.

Number of pounds could be in decimals.

The value of w = 2.5 represents 2.5 pounds of walnuts.

On plugging w=2.5 in c=6.4w equation, we get.

c=6.4×2.5 = $16.

Therefore, for 2.5 pounds of walnuts the total cost is $16.

Hence, <u>a value of 2.5 for w make sense in this situation. It shows that cost of 2.5 pounds of walnuts is $16, where cost of each pound of walnuts is 6.4.</u>

6 0

3 years ago

The scale on a map states that 1 centimeter corresponds to 20 kilometers. On the map, two cities are 0.3 cm apart. Find the actu

Archy [21]

Answer: The actual distance is 6 km

Step-by-step explanation: If you do a conversion from 1 cm to 20 km in fraction form, you will have

$\frac{1cm}{20km} = \frac{0.1cm}{km ?}$

So, if you solve for km, you will get 6 using cross multipulcation

6 0

3 years ago

–(7)-¹

MaRussiya [10]

$(-5)^{-6}(-5)^9$

$= (-5)^{-6+9}$

$= (-5)^{3}$

$(4 \times 10^{10})(9 \times 10^{-6})$

$= 36 \times 10^{10-6}$

$= 36 \times 10^{4}$

3 0

3 years ago

How do you even become a moderator/admin on here do u sign up orrr

dalvyx [7]

Contact one and see what they say

7 0

3 years ago