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andrew-mc [135]
4 years ago
15

A word that means to squeeze a gas in to a smaller place

Physics
2 answers:
Leona [35]4 years ago
6 0
I think the best word here would be compress. It is to compress that is defined as to squeeze a gas into a smaller space. Compression is the reduction of volume which cause an increase in pressure of the gas. Hope this answers the question. Have a nice day.

PilotLPTM [1.2K]4 years ago
6 0
Compress is probably the best answer
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The action of two forces. One is a forward force of 1157 N provided by traction between the wheels and the road. The other is a
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Complete question

A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.

Answer:

The car must travel 68.94 meters.

Explanation:

First, we are going to find the acceleration of the car using Newton's second Law:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

with m the mass , a the acceleration and \sum\overrightarrow{F} the net force forces that is:

(F-f) (2)

with F the force provided by traction and f the resistive force:

(2) on (1):

(F-f)=ma

solving for a:

a=\frac{F-f}{m} =\frac{1157N-902N}{2700kg} =0.094\frac{m}{s^{2}}

Now let's use the Galileo’s kinematic equation

Vf^{2}=Vo^{2}+2a\varDelta x (3)

With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and \varDelta x the time took to achieve that velocity, solving (3) for \varDelta x:

\varDelta x= \frac{Vf^{2}}{2a} = t= \frac{(3.6\frac{m}{s})^2}{2*0.094\frac{m}{s^{2}}}

t=68.94 m

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Given that,

Mass of object, m = 55 kg

Mechanical energy of the object, M = 4306 J    

Potential energy, P = 2940 J

We know that the mechanical energy is the sum of kinetic and potential energy such that,

Mechanical energy = kinetic energy + potential energy

K=M-P\\\\K=4306-2940\\\\K=1366\ J

Kinetic energy is given by :

K=\dfrac{1}{2}mv^2v is velocity of object

v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1366}{55}} \\\\v=7.04\ m/s

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