If the speed of sound in air is 340 m/s, what is approximately the length of the shortest air column closed at one end that will
1 answer:
Answer:
42.9 cm
Explanation:
given,
speed of sound, v = 340 m/s
Frequency of tuning fork, f = 198 Hz
The length of the shortest air column closed at one end.
this is the case of the standing wave.
L = N λ
N = the number of complete sine waves in the standing wave.
The standing wave in the problem is the first harmonic of a pipe open at one end.
N = 1/4
we know,
v = f λ
340 = 198 x λ
λ = 1.717 m
now,
L = N λ
L = 42.9 cm
minimum length of the required pipe is 42.9 cm.
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Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ = = sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser