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nalin [4]
3 years ago
14

What are some of the challenges that face wave energy production?

Physics
2 answers:
valentina_108 [34]3 years ago
4 0

Answer:

One of the major obstacles with any wave resource study is lack of long-term ocean wave measurements inside the 100-meter-depth contour, where refraction effects result in spatially inhomogeneous wave parameters. Lack of data makes it difficult or impossible to mark the optimum locations for WECs.

Explanation:

dlinn [17]3 years ago
3 0

Answer:

WEC Challenges

One of the major obstacles with any wave resource study is lack of long-term ocean wave measurements inside the 100-meter-depth contour, where refraction effects result in spatially inhomogeneous wave parameters. Lack of data makes it difficult or impossible to mark the optimum locations for WECs

Explanation:

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How much force is required to move a sled 5 meters if a person uses 60 j of work? 300N 12N 65N 30N
maksim [4K]
The answer is b 12N because
We know that<span>
W = F × d × c o s(θ)</span>
assuming theta=0 we then solve and have<span>
F=<span>W/d</span></span>
substitute known values to get:<span><span>
F=<span><span>60J/</span><span>5m</span></span>=12N</span></span>
4 0
3 years ago
8892 ml to grams then to mg ​
andrew11 [14]

Answer:

8892 ml = 8892 gm = 8892000 mg

1 ml = 1 gram

8892 ml = 8892 gram

1 gram or ml = 1000 milligram

8892 ml = 8892 × 1000 = 8892000 milligram

hope this helps

have a good day :)

Explanation:

remember: 1 kilogram = 1000 gram = 1000000 milligram.

Milliliter is expressed same as gram and liter is expressed same as kilogram.

1 meter = 100 cm, 1 kilometer = 1000 meter,

1 cm = 10 millimeter.

7 0
3 years ago
Read 2 more answers
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
konstantin123 [22]

Answer:

I=2.71\times 10^{-5}\ A

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.  

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}, r is radius

Let I is the displacement current. It is given by :

I=C\dfrac{dV}{dt}

Here, \dfrac{dV}{dt} is rate of increasing potential difference

So

I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A

So, the value of displacement current is 2.71\times 10^{-5}\ A.

4 0
3 years ago
A cyclical heat engine, operating between temperatures of 450º C and 150º C produces 4.00 MJ of work on a heat transfer of 5.00
gogolik [260]

Answer:

(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%

Explanation:

Using the formula that relate heat and work from the thermodynamic theory as:W=Q=Q_{in}-Q_{out} solving to Q_out we get:Q_{out}=Q_{in}-W=5(MJ)-4(MJ)=1(MJ) this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us: n=1-\frac{T_{Low} }{T_{High}} where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get:n=1-\frac{423.15}{723.15} =0.415=41.5%

5 0
3 years ago
A truck’s engine produces 20,000 N of force. It dumps its load and its mass is reduced to 10,000 kg. What is the acceleration of
spayn [35]

Explanation:

If F = m*a, we can easily solve for a.

a = 20000/10000

7 0
3 years ago
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