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3 years ago

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What is the meaning of sound media component

1 answer:

Artist 52 [7]3 years ago

5 0

Answer:

prerecorded magnetic tapes used for noncommercialplayback of sound on audio equipment.

Explanation:

study hard:)

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Superman throws a 2400 n boulder at a villain. what horizontal force must superman apply to the boulder to give a horizontal acc

Ksenya-84 [330]

The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:
$W=mg$
Rearranging the relationship, we can calculate the mass of the boulder:
$m= \frac{W}{g}= \frac{2400 N}{9.81 m/s^2}=244.6 kg$

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is $a=12.0 m/s^2$ . We can find the force applied by using Netwon's second law of motion:
$F=ma=(244.6 kg)(12.0 m/s^2)=2935 N$

4 0

3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

8 0

3 years ago

Can someone please help me out

tia_tia [17]

Answer:

its 0

Explanation:

because there is only 4999 right so its 0

4 0

3 years ago

Read 2 more answers

A 4.00 kg stone is dropped from a height of 145 m. What is the stone’s potential and kinetic energy respectively when it is 50.0

Lorico [155]

Answer:

C - 3,720 J, 1,950 J

Explanation:

Hello

Epotential = M*G*H

Ep = (4)(9.8)(145-50)

Ep = 3729 J

Then

Ec = 1950 J

Best regards

6 0

3 years ago

A sound wave has a frequency of 1,395 Hertz. All sound waves in air travel

Kryger [21]

V= fx lambda
lambda, or wavelength= v/f
=343/1395
=0.25 m.

5 0

3 years ago