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2 years ago

What is the meaning of sound media component

Physics

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

prerecorded magnetic tapes used for noncommercialplayback of sound on audio equipment.

Explanation:

study hard:)

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a flowerpot falls from a windowsill 25m above the sidewalk how fast is the flowerpot moving when it strikes the ground

Mariana [72]

s = 25m

v = ?

a = 9.81m/s²

v² = u² + 2as

v² = 0 + 2x9.81x25

v² = 490.5

v = √490.5

= 22.15m/s

3 0

3 years ago

The greatest ocean depths on earth are found in the Marianas Trench near the Philippines, where the depth of the bottom of the t

kompoz [17]

Answer:

103063860 Pa

Explanation:

$\rho$ = Density of seawater = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth at which pressure is being measured = 10.2 km

The gauge pressure is given by

$p=\rho gh\\\Rightarrow p=1030\times 9.81\times 10.2\times 10^3\\\Rightarrow p=103063860\ Pa$

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa

3 0

3 years ago

Suppose that a baseball is tossed up into the air at an initial velocity 1818\text{ m/s} m/s. The height of the baseball at t

olga2289 [7]

Answer:

13.1 m/s

Explanation:

Given that a baseball is tossed up into the air at an initial velocity 18 m/s. The height of the baseball at time t in seconds is given by h(t) = 18t−4.9t 2 (in meters).

a) What is the average velocity for [1,1.5]?

To calculate the velocity travelled by the ball, differentiate the function.

dh/dt = 18 - 9.8t

Substitute t for 1 in the above Differential function

dh/dt = 18 - 9.8 (1)

But dh/dt = velocity

V = 18 - 9.8

V = 8.2 m/s

Average velocity = ( U + V ) / 2

Average velocity = (18 + 8.2)/2

Average velocity = 26.2/2

Average velocity = 13.1 m/s

5 0

3 years ago

Classify the quadrilateral. parallel sides are indicated with arrows.

Sonbull [250]

A quadrilateral is a four-sided polygon that may be classified as: trapezoid, rectangle, square, rhombus, etc. This classification is based on the measurement of the four angles, the four sides, and their being parallel. Unfortunately though, I think you missed to include here the diagram that we are about to classify.

4 0

3 years ago

After enjoying a tasty meal of the first moth, the bat goes after another moth. Flying with the same speed and emitting the same

Aleksandr-060686 [28]

This question is incomplete, the complete question is;

A bat flies towards a moth at 7.1 m/s while the moth is flying towards the bat at 4.4 m/s. The bat emits a sound wave of 51.7 kHz.

After enjoying a tasty meal of the first moth, the bat goes after another moth. Flying with the same speed and emitting the same frequency, this time the bat detects a reflected frequency of 55.5 kHz. How fast is the second moth moving

Answer:

the second moth is moving at 5.062 m/s

Explanation:

Given the data in the question;

Using doppler's effect

$f_{moth$ = f₀( $v_{s$ ± $v_{observer$ / $v_{s$ ± $v_{source$ )

f₁ = f₀( ( $v_{s$ + v₂) / ( $v_{s$ - v₁ ) )

frequency reflected from the moth,

Now, moth is the source and the bat is the receiver

f₂ = f₁( ( $v_{s$ + v₁ ) / ( $v_{s$ - v₂ ) )

hence, f = f₀[ ( ( $v_{s$ + v₁ ) / ( $v_{s$ - v₂ ) ) ( ( $v_{s$ + u₂ ) / ( $v_{s$ - u₁ ) )

we know that, the velocity of sound $v_{s$ = 343 m/s.

given that v₁ and v₂ { velocity of bat } = 7.1 m/s, f₀ = 51.7 kHz and f = 55.5 kHz.

we substitute

55.5 = 51.7[ ( ( 343 + 7.1 ) / ( 343 - 7.1 ) ) ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 51.7[ ( 350.1 / 335.9 ) ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 51.7[ 1.04227 ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 = 53.885359 ( ( 343 + u ) / ( 343 - u ) ) ]

55.5 / 53.885359 = ( 343 + u ) / ( 343 - u )

1.02996 = ( 343 + u₂ ) / ( 343 - u )

( 343 + u₂ ) = 1.02996( 343 - u )

343 + u = 353.27628 - 1.02996u

u + 1.02996u = 353.27628 - 343

2.02996u = 10.27628

u = 10.27628 / 2.02996

u = 5.062 m/s

Therefore, the second moth is moving at 5.062 m/s

4 0

3 years ago