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gulaghasi [49]
3 years ago
9

What is the IMA of the following pulley system?

Physics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer ideal mechanical advantage

Irina-Kira [14]3 years ago
7 0
The full form of IMA is an “ideal mechanical advantage”
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The principle of alignment means that you use conventions of typography, layout, color, and other visual elements to make sure t
vitfil [10]

Answer: True

Explanation:

The principle of alignment means that conventions of typography such as; layout, color, and other visual elements should be used to make sure that readers easily access your most important content of a document. These cues call the attention of the readers to the most important sections of the document which you want them to really see.

7 0
3 years ago
When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 2.5 x 10-15 m before
Tasya [4]

Explanation:

It is given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, d=2.5\times 10^{-15}\ m

Speed of light, c=3\times 10^{8}\ m\s

Let t is the time interval required for the strong interaction to occur. The speed is given by :

c=\dfrac{d}{t}

t=\dfrac{d}{c}

t=\dfrac{2.5\times 10^{-15}\ m}{3\times 10^{8}\ m/s}

t=8.33\times 10^{-24}\ s

So, the time interval required for the strong interaction to occur is 8.33\times 10^{-24}\ s. Hence, this is the required solution.

8 0
3 years ago
An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch
gayaneshka [121]

Answer:

Explanation:

Solution is in the picture attached

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3 years ago
Consider an old-fashion bicycle with a small wheel of radius 0.17 m and a large wheel of radius 0.92 m. Suppose the rider starts
Gala2k [10]

Answer:

10259.6 m

Explanation:

We are given that

Radius of small wheel,r=0.17 m

Radius of large wheel,r'=0.92 m

Initial velocity,u=0

Time,t=2.7 minutes=162 s

1 min=60 s

Velocity,v=10m/s

Time,t'=13.7 minutes=822 s

Time,t''=4.1 minutes=246 s

v=u+at

Substitute the values

10=0+162a=162a

a=\frac{10}{162}=0.0617m/s^2

s=ut+\frac{1}{2}at^2

Substitute the values

s=\frac{1}{2}(0.0617)(162)^2=809.6 m

s'=vt'=10\times 822=8220 m

a'=\frac{v}{t''}=\frac{10}{246}

s''=\frac{1}{2}a't''^2=\frac{1}{2}\times \frac{10}{246}(246)^2=1230 m

Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m

6 0
3 years ago
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When a falling object reaches terminal velocity, the net force acting on it is
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Pretty sure that it is 0.
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