Answer
given,
mass of ice hockey player = 110 Kg
initial speed of the skate = 3 m/s
final speed of the skate = 0 m/s
distance of the center of mass, m = 30 cm = 0.3 m
a) Change in kinetic energy
b) Average force must he exerted on the railing
using work energy theorem
W = Δ KE
F .d = -495
F x 0.3 = -495
F = -1650 N
the average force exerted on the railing is equal to 1650 N.
Answer:
F = -4567.40 N
Explanation:
Given that,
The power developed by the engine, P = 196 hp
1 hp = 746 W
196 hp = 146157 W
Speed of the car, v = 32 m/s
Let F is the total friction force acting on the car. The product of force and velocity is called the power developed by the engine. It is given by :
F = -4567.40 N
So, the total frictional force acting on the car is 4567.40 N. Hence, this is the required solution.