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Karolina [17]
3 years ago
6

Justin strikes a 0.058-kg golf ball with a force of 260 N. If the ball moves with a velocity of 63 m/s, calculate the time the b

all is in contact with the club
Physics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

0.014s

Explanation:

Given parameters:

Mass of the ball  = 0.058kg

Force  = 260N

Velocity of the ball  = 63m/s

Unknown:

Time of contact  = ?

Solution:

To solve this problem, we apply Newton's second law of motion which is mathematically expressed as;

    Ft  = m(v - u)

F is the force

t is time

m is the mass

v is the final velocity

u is the initial velocity = 0m/s

   Insert the parameters and find t;

      260 x t  = 0.058(63 - 0)

       260t  = 3.65

            t = 0.014s

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Explanation:

Given

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At this radius, what is the magnitude of the net force that maintains circular motion exerted on the pilot by the seat belts, th
Ainat [17]

Answer:

Fc=5253 N

Explanation:

Answer:

Fc=5253 N

Explanation:

sequel to the question given, this question would have taken precedence:

"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."

so we derive centripetal acceleration first

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( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.

he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.

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