Fnet = (mass) (acceleration)
= 11 kg x 3.7m/s^2
= 41 N
Answer:
the reflected wave is inverted and the transmitted wave is up
Explanation:
To answer this question we must analyze the physical phenomenon, with an wave reaching a discontinuity, we can analyze it as a shock.
Let's start when the discontinuity is with a fixed, very heavy and rigid obstacle, in this case the reflected wave is inverted, since the contact point cannot move
In the event that it collides with an object that can move, the reflected wave is not inverted, this is because the point can rise, they form a maximum at this point.
In the proposed case the shock is when the thickness changes, in this case we have the above phenomena, a part of the wave is reflected by being inverted and a part of the wave is transmitted without inverting.
The amplitude sum of the amplitudes of the two waves is proportional to the lanería that is distributed between them.
When checking the answers the correct one is the reflected wave is inverted and the transmitted wave is up
Turn lights off, unplug electronics, and use solar energy
Answer: 114
Explanation:
The mass number of an element gives the sum of the protons and the neutrons inside the nucleus of one atom of that element, while the atomic number of an element gives the number of protons inside one atom of that element.
We can infer the number of neutrons inside one atom of Osmium from its mass number and atomic number.
The atomic number of osmium is 76, so each atom of osmium has 76 protons
The (average) mass number of osmium is 190, so each atom of osmium has (on average) 190 protons+neutrons
So, in order to find the average number of neutrons, we can subtract the atomic number from the mass number:

Answer:
Force, 
Explanation:
It is given that,
Length of the room, l = 4 m
breadth of the room, b = 5 m
Height of the room, h = 3 m
Atmospheric pressure, 
We know that the force acting per unit area is called pressure exerted. Its formula is given by :




So, the total force on the floor due to the air above the surface is
. Hence, this is the required solution.