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3 years ago

Which diagram correctly demonstrates the various forces acting on a ball moving horizontally with some speed?

Physics

2 answers:

cestrela7 [59]3 years ago

6 0

Answer:

I think it i either the 1st one with all the arrows pointing to the ball because it has some speed so it is going fast horizontally 2) the ball has to stay on the ground so that's where the gravitational pull comes in (the arrow pointing down and pointing up). 3) when the ball is moving horizontally the air which is pushing the ball from the left pushes it back a little hence slowing it a little.

Explanation:

This is my guess anyways, feel free to choose this answer my second opinon was the second one which is the one with the arrow pointing down and arrow pointing right and left ( the one which says movement of the ball )

VLD [36.1K]3 years ago

4 0

Answer:

Option A)

Explanation:

Here we know that ball is moving horizontally so the force on the ball perpendicular to the plane must be balanced

We can say that gravitational force "mg" is balanced by the normal force due to ground. Which shows that two equal and opposite arrows must be there on ball in vertical direction.

Now in horizontal direction there may be unbalanced force in two directions.

One of the force may be due to air drag and friction on the ground. While other force is due to some external agent.

So here correct answer is represented by first figure or we can say it is given by

Option A)

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Archimedes supposedly was asked to determine whether a crown made for the king consisted of pure gold (density of gold is 19.3 ×

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Answer:

Explanation:

First, we can find the mass of the object in air

Since W = mg

m = W/g = (8.9)/(9.8) = 0.908 kg

Then, by Archimedes principle, we can find its volume. The volume is found by the weight of the water displaced by the formula

W = Vρg

The Weight is the difference in scale readings. The density of water is 1000 kg/m3

(8.9- 7.8) = V(1000)(9.8)

Thus V = 1 X 10-4 m3

Then, since density is mass / volume

ρ = 0.908/1 X 10-4

ρ = 8254 kg/m3 which is 8 X 103 kg/m3

The density of gold is 19.3 X 103 kg/m3

Since those densities are not the same, the crown is either hollow or not pure gold

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3 years ago

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An electric current can have no current when the switch is OPEN

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4 years ago

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When you look at yourself in a convex mirror, you appear to be ¼ your actual size. If you are standing 1.0 m in front of the mir

Nookie1986 [14]

Answer:

The focal length is $f = -0.2 \ m$

The radius of curvature is $R = -0.4 \ m$

Explanation:

From the question we are told that

The magnification of the mirror is $m = \frac{1}{2}$

The distance of the person from the mirror(the object distance ) is $u = - 1.0 \ m$

The negative sign shows that it is been placed in front of the mirror

Generally the magnification of the mirror is mathematically represented as

$m = \frac{v}{u}$

=> $\frac{1}{4} = \frac{v}{-u}$

=> $v = \frac{- 1}{4}$

Generally from the lens equation we have that

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

=> $\frac{1}{f} = \frac{1}{-1 } + \frac{1}{-\frac{1}{4} }$

=> $f = -0.2 \ m$

Generally the radius of curvature is mathematically represented as

$R = 2 * f$

=> $R = 2 * - 0.2$

=> $R = -0.4 \ m$

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3 years ago

What is the amount of force required to accelerate a 20 kg object to 5 m/s˛?

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Answer:

Force = 100N

Explanation:

Force = mass × acceleration

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3 years ago

Attempt 2 You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 15151515 l

Natasha_Volkova [10]

Answer:

v = 28.98 ft / s

Explanation:

For this problem we must solve it in parts, let's start by looking for the speed of the two cars after the collision

In the exercise they indicate the weight of each car

Wₐ = 1500 lb

W_b = 1125 lb

Car B's velocity from v_b = 42.0 mph westward, car A travels east

let's find the mass of the vehicles

W = mg

m = W / g

mₐ = Wₐ / g

m_b = W_b / g

mₐ = 1500/32 = 46.875 slug

m_b = 125/32 = 35,156 slug

Let's reduce to the english system

v_b = 42.0 mph (5280 foot / 1 mile) (1h / 3600s) = 61.6 ft / s

We define a system formed by the two vehicles, so that the forces during the crash have been internal and the moment is preserved

we assume the direction to the east (right) positive

initial instant. Before the crash

p₀ = mₐ v₀ₐ - m_b v_{ob}

final instant. Right after the crash

p_f = (mₐ + m_b) v

the moment is preserved

p₀ = p_f

mₐ v₀ₐ - m_b v_{ob} = (mₐ + m_b) v

v = $\frac{ m_a \ v_{oa} - m_b \ v_{ob} }{ m_a +m_b}$

we substitute the values

v = $\frac{ 46.875}{82.03} \ v_{oa} - \frac{35.156}{82.03} \ 61.6$

v = 0.559 v₀ₐ - 26.40 (1)

Now as the two vehicles united we can use the relationship between work and kinetic energy

the total mass is

M = mₐ + m_b

M = 46,875 + 35,156 = 82,031 slug

starting point. Jsto after the crash

K₀ = ½ M v²

final point. When they stop

K_f = 0

The work is

W = - fr x

the negative sign is because the friction forces are always opposite to the displacement

Let's write Newton's second law

Axis y

N-W = 0

N = W

the friction force has the expression

fr = μ N

we substitute

-μ W x = Kf - Ko

-μ W x = 0 - ½ (W / g) v²

v² = 2 μ g x

v = $\sqrt{ 2 \ 0.750 \ 32 \ 17.5}$ Ra (2 0.750 32 17.5

v = 28.98 ft / s

3 0

3 years ago

Which diagram correctly demonstrates the various forces acting on a ball moving horizontally with some speed?​

Which diagram correctly demonstrates the various forces acting on a ball moving horizontally with some speed?