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Karo-lina-s [1.5K]
3 years ago
6

Do deaf children go through the four stages of acquiring language? Use what you’ve read in the chapter to explain why or why not

. Further, explain any differences and/or similarities that may take place.
Physics
1 answer:
sdas [7]3 years ago
4 0
No deaf children dont. im deaf and i dident go through those stages.

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Can a measurement be exact
Ulleksa [173]

Can a measurement be exact? No

3 0
3 years ago
The energy change in an endothermic reaction is: A. Internal B. External C. Negative D. Positive
77julia77 [94]

Answer:

Positive

Explanation:

In an endothermic reaction, the products are at a higher energy than the reactants. This means that the enthalpy change of the reaction (∆H) is positive

4 0
2 years ago
A battery is replaced with one of lower emf. State and explain how the resistance of the lamps would have to change in order to
kow [346]

The brightness of the lamp is proportional to the current flowing through the lamp: the larger the current, the brighter the lamp.

The current flowing through the lamp is given by Ohm's law:

I=\frac{V}{R}

where

V is the potential difference across the lamp, which is equal to the emf of the battery, and R is the resistance of the lamp.

The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.

3 0
3 years ago
In a real isothermal expansion, the temperature of the surroundings must be________the temperature of the gas.
Lady_Fox [76]
Must be isolated from the temperature of the gas
7 0
2 years ago
¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!
asambeis [7]

Answer:

(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

Explanation:

(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J

The electric potential is given by

W = q V

40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V

(b)

charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m

Let the potential is V.

V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V

(c)

Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V

Let the charge is q.

W= q V

8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C

3 0
2 years ago
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