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sergeinik [125]
3 years ago
10

Identify a true statement about flow separation. Multiple Choice A. Flow separation is caused due to high temperature gradient i

n the flowing fluid. B. Flow separation is caused due to viscosity difference in the flowing fluid. C. Flow separation is caused due to density difference in the flowing fluid. D. Flow separation is caused due to adverse pressure gradient in the flowing fluid.
Physics
1 answer:
Helga [31]3 years ago
6 0

Answer:

D. Flow separation is caused due to adverse pressure gradient in the flowing fluid.

Explanation:

Flow separation  :    

  When adverse pressure gradient become dominate then phenomenon of flow separation occurs.In the other words when boundary layer is form against the adverse pressure then  phenomenon of flow separation occurs.The adverse pressure means a opposing which act in the opposite to the direction of fluid flow.Due to flow separation eddy formation occurs and these eddy leads to increases the losses in the fluid flow.Due to flow separation fluid leaves the solid surface and form eddies.

So the answer is D.              

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Answer:

transverse wave: A wave in which particles of the medium move at right angles to the direction of the wave is called a transverse wave.

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A solenoid is created by wrapping a L = 85 m long wire around a hollow tube of diameter D = 2.5 cm. The wire diameter is d = 0.7
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How many coffee beans selling for $1.20 per pound should be mixed with 3 pounds of coffee beans selling for $2.40 per pound to o
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What do we call the distance labeled from A to B and what could we do to the note played on an instrument to change that distanc
Korvikt [17]

Correct answer choice is :


A) From A to B is known as the wavelength and changing the pitch of the note will change its length.


Explanation:


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7 0
3 years ago
Read 2 more answers
What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is
QveST [7]
Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "

Solution
The force exerted on a charge q by an electric field E is given by
</span>F=qE
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>E=k_e  \frac{Q}{r^2}
with k_e = 8.99\cdot 10^9 Nm^2/C^2, Q=+25 nC=25 \cdot 10^{-9}C is the charge on the bead. We want to calculate the field at r=4.0 cm=0.04 m:
E=(8.99\cdot 10^9) \frac{25\cdot 10^{-9}}{(0.04)^2}=1.4\cdot 10^5 V/m
The proton has a charge of q=1.6\cdot 10^{-19}C, therefore the force exerted on it is
F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N

And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass, m=1.67\cdot 10^{-27} kg, we have
F=ma
a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2

The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
a=-1.35 \cdot 10^{13} m/s^2
6 0
4 years ago
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