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nydimaria [60]
2 years ago
9

A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i

ts tires will not leave the track? Round to one decimal place and include units. Image:

Physics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

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What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

3 0
3 years ago
Most ocean waves obtain their energy and motion from _____. the moon's gravitational attraction the sun plate movement the wind
IrinaVladis [17]
Hello!

Most ocean waves obtain their energy and motion from the wind.

Ocean waves are surface waves that move across the surface of the ocean. When wind touches the surface of the water, there is friction in the contact zone. This friction causes a drag effect, that makes wrinkles on the surface of the water. As the wrinkles get bigger, they transform into full-blown waves, and the taller the wave, the more energy it can extract from the wind, making them even bigger and to move longer distances. 

Have a nice day!


3 0
2 years ago
a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n
RSB [31]

Answer:

we use the formula,

v {}^{2}  = u {}^{2}  + 2gh

89 {}^{2}  = 76 {}^{2}  + 2(10)h

h = (89 {}^{2}  - 76 {}^{2} ) \div 20

h= 107 m

5 0
3 years ago
A ball is released from a tower at a height of 100 meters toward the roof of another tower that is 25 meters high. The horizonta
I am Lyosha [343]
-- During the time the ball is flying from the high roof to the low roof,
it's going to fall (100-25) = 75 meters.
How long does it take an object dropped from rest to fall 75 meters ?

Distance = (1/2) · (gravity) · (time)²

75 m = (4.9 m/s²) · (time)²

Time² = (75 m) / (4.9 m/s²)
Time² = 15.31 sec²
Time = √(15.31 sec²)  =  3.91 seconds 

So the ball has to cover the horizontal distance of 20 meters 
in 3.91 seconds.

Distance = (speed) · (time)

20 m = (speed) · (3.91 sec)

Speed = (20 m) / (3.91 sec)

Speed  =  5.11 m/s
7 0
2 years ago
You use a slingshot to launch a potato horizontally from the edge of a cliff with speed v0. The acceleration due to gravity is g
sergij07 [2.7K]

Answer:

 t = 2 v₀ / g

Explanation:

For this projectile launch exercise we use the displacement equations

        x = vox t

       y = y₀ + v_{oy} t - ½ g t²

As it is launched horizontally the vertical velocity is zero and the point of origin of the coordinate system is here, so y₀ is zero.

       x = v₀ t

       y = ½ g t²

They ask us for the time for which

        x = y

        vo t = ½ g t²

         t = 2 v₀ / g

8 0
2 years ago
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