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nydimaria [60]
3 years ago
9

A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i

ts tires will not leave the track? Round to one decimal place and include units. Image:

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

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3 years ago
A 6.0 MeV alpha particle beam of cross section 5 cm2 is completely stopped in an ionization chamber producing a saturation curre
Licemer1 [7]

Answer:

v=6.0MeV\\h=6.626\cdot10^{-34}\\dq=33\\

Solution

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Explanation:

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6 0
4 years ago
How do I find time?
kari74 [83]

<u>Answer:</u>   3

H = 45 m ,

time required for the stone

  S = u.t+(1/2) g.t²

45  = (1/2) 9.81. t²      since u( initial velocity) = 0 ; S =H.

 t²  = 9.17 s

<em>  t = 3.02 s  </em>

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6 0
3 years ago
The experimenter fom the video rotates on his stool, this time holding his empty hands in his lap. You stand on a desk above him
gtnhenbr [62]

Answer:

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We are applying no torque from outside . therefore , the angular momentum will remain the same

Thus angular momentum L = I ω = constant

Thus we can say I₁ ω₁ = I₂ω₂ = constant

here I₁ is the initial moment of inertia and ω₁ is the initial angular velocity

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When a been bag is dropped on his lap , his moment of inertia increases due to increase in mass

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7 0
3 years ago
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marusya05 [52]

Answer:

2A

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I = 24/12 = 2A.

5 0
4 years ago
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