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kvasek [131]
3 years ago
8

d. Still worried that the tea party will last too long, the lawyer makes sure each guest has a spoon. Give a scientific reason w

hy this would help. (1 point) e. The lawyer's daughter (who is taking chemistry in high school) suggests that her mother serve hot tea instead of iced tea. Give a scientific reason why this would speed things up. (1 point) f. Normally the solubility of sugar in hot tea is about 700 g for a cup of tea, yet one guest dissolved 750 g of sugar in his tea. What kind of solution did he have
Chemistry
1 answer:
Dvinal [7]3 years ago
7 0

d. Stirring using a spoon increases causes the solutes to come more in contact with solvent and easy reduction in temperature.

e. Reaction rates increases with increase in temperature.

f. A supersaturated solution

Explanation:

For d:

Stirring of the tea using a spoon will cause the dissolution of sugar in the tea faster. This helps to expose more surface area of the particles to the action of the solvent. Through stirring, more heat can also be easily lost. The spoon goes in between the flowing liquid which allows for heat trying to be trapped to eventually escape.

  1. Reactions increases when more surface area is available for the solute contact with the solvent.
  2. Using a spoon to stir the mixture will further enhance the rate of the reaction. More of the solute will freely come into close contact with the solvent and dissolution will proceed much faster.

For e:

The rate of chemical reactions is directly proportional to increase in temperature. It is quite known that for every 10°C rise in temperature, reaction rates will double.

  • increase in temperature causes the kinetic energy of the of each of the reacting particles to increase.
  • the frequency of collision increases due to the increasing temperature.

For f:

A supersaturated solution is a solution that contains more of the solute than it normally hold at that temperature if crystals of the solute were present. This kind of solution is quite unstable.

  • The normal saturated solution is for a cup of tea to dissolve 700g of sugar. A saturated solution is one that contains the maximum amount of substance that it can dissolve at that temperature.
  • If the amount of sugar exceeds the normal amount, then a super-saturated solution is formed.

Learn more:

brainly.com/question/2802008

#learnwithBrainly

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You dissolve 8.65 grams of lead(l) nitrate in water and then you add 2 50 grams of aluminum. This reaction occurs 2AI(S)+ 3Pb(NO
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<u>Answer:</u> The theoretical yield of solid lead comes out to be 5.408 grams.

<u>Explanation:</u>

To calculate the moles, we use the following equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

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Given mass of lead nitrate = 8.65 grams

Molar mass of lead nitrate = 331.2 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{8.65g}{331.2g/mol}=0.0261moles

  • <u>Moles of Aluminium:</u>

Given mass of aluminium = 2.5 grams

Molar mass of aluminium = 27 g/mol

Putting values in above equation, we get:

\text{Number of moles}=\frac{2.5g}{27g/mol}=0.0925moles

For the given chemical reaction, the equation follows:

2AI(s)+3Pb(NO_3)_2(aq.)\rightarrow 3Pb(s)+2AI(NO3)_3(aq.

By Stoichiometry:

3 moles of lead nitrate reacts with 2 moles of aluminium

So, 0.0261 moles of lead nitrate are produced by = \frac{2}{3}\times 0.0261=0.0174moles of aluminium.

As, the required amount of aluminium is less than the given amount. Hence, it is considered as the excess reagent.

Lead nitrate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of lead nitrate are produces 3 moles of lead metal.

So, 0.0261 moles of lead nitrate will produce = \frac{3}{3}\times 0.0261=0.0261moles of lead metal.

  • Now, to calculate the grams or theoretical yield of lead metal, we put in the mole's equation, we get:

Molar mass of lead = 207.2 g/mol

Putting values in above equation, we get:

0.0261mol=\frac{\text{Given mass}}{207.2g/mol}

Mass of lead = 5.408 grams

Hence, the theoretical yield of solid lead comes out to be 5.408 grams.

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