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kvasek [131]
3 years ago
8

d. Still worried that the tea party will last too long, the lawyer makes sure each guest has a spoon. Give a scientific reason w

hy this would help. (1 point) e. The lawyer's daughter (who is taking chemistry in high school) suggests that her mother serve hot tea instead of iced tea. Give a scientific reason why this would speed things up. (1 point) f. Normally the solubility of sugar in hot tea is about 700 g for a cup of tea, yet one guest dissolved 750 g of sugar in his tea. What kind of solution did he have
Chemistry
1 answer:
Dvinal [7]3 years ago
7 0

d. Stirring using a spoon increases causes the solutes to come more in contact with solvent and easy reduction in temperature.

e. Reaction rates increases with increase in temperature.

f. A supersaturated solution

Explanation:

For d:

Stirring of the tea using a spoon will cause the dissolution of sugar in the tea faster. This helps to expose more surface area of the particles to the action of the solvent. Through stirring, more heat can also be easily lost. The spoon goes in between the flowing liquid which allows for heat trying to be trapped to eventually escape.

  1. Reactions increases when more surface area is available for the solute contact with the solvent.
  2. Using a spoon to stir the mixture will further enhance the rate of the reaction. More of the solute will freely come into close contact with the solvent and dissolution will proceed much faster.

For e:

The rate of chemical reactions is directly proportional to increase in temperature. It is quite known that for every 10°C rise in temperature, reaction rates will double.

  • increase in temperature causes the kinetic energy of the of each of the reacting particles to increase.
  • the frequency of collision increases due to the increasing temperature.

For f:

A supersaturated solution is a solution that contains more of the solute than it normally hold at that temperature if crystals of the solute were present. This kind of solution is quite unstable.

  • The normal saturated solution is for a cup of tea to dissolve 700g of sugar. A saturated solution is one that contains the maximum amount of substance that it can dissolve at that temperature.
  • If the amount of sugar exceeds the normal amount, then a super-saturated solution is formed.

Learn more:

brainly.com/question/2802008

#learnwithBrainly

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determine whether the aqueous solutions of each of the following salts will be acidic, basic, or neutral
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KCl is neutral because KOH is a strong base and HCl is a strong acid

To determine if the salt is neutral, acidic or basic, determine how the salt was made, or from which acid and base it was derived. Once we have determined how the salt was made, determine if the acid and base are both strong, weak or one of each.  If both are strong (e.g. NaOH + HCl), then the salt (NaCl) is NEUTRAL.  If the base is strong and the acid is weak (KOH + HCN), then the salt (KCN) is BASIC.  IF the base is weak and the acid is strong (NH3 + HCl), then the salt (NH4Cl) is ACIDIC.  If both the base and the acid are weak (NH3 + CH3COOH), then then salt (CH3COONH4) will have a pH determined by which is stronger (the acid or the base) and this will depend on the Ka of the weak acid compared to the Kb of the weak base.

KCl is neutral because KOH is a strong base and HCl is a strong acid NaCN is generally basic because NaOH is a strong base and HCN is a very week acid. NH4NO3 is usually acid because HNO3 is a strong acid and NH4OH is a week base

CH3COONH4 is exactly neutral because both NH4OH ad CH3COOH are respectively week base and week acid. Moreover, the Ka of acetic acid is exactly equal to the Kb of NH4OH

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Structure can affect the Ka values for related acids. In the boxes below, draw the complete Lewis structure for a single ion of
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Answer:

Explanation: see attachment below

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Calculate the solubility of o2 in water at a partial pressure of o2 of 120 torr at 25 ̊c. the henry's law constant for o2 at 25
Vladimir79 [104]

Answer:

1) 2.054 x 10⁻⁴ mol/L.

2) Decreasing the temperature will increase the solubilty of O₂ gas in water.

Explanation:

1) The solubility of O₂ gas in water:

  • We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,
  • where, Cgas is the solubility if gas,
  • K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),
  • P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).
  • Cgas = K P = (1.3 x 10⁻³ mol/l atm) (0.158 atm) = 2.054 x 10⁻⁴ mol/L.

2) The effect of decreasing temperature on the solubility O₂ gas in water:

  • Decreasing the temperature will increase the solubilty of O₂ gas in water.
  • When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.
  • Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.


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