Question

Solid aluminum hydroxide reacts with a solution of hydrobromic acid. Write a balanced molecular equation and a balanced net ionic equation

Answer 1

Answer:

$Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)$

$Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)$

Explanation:

Aluminium hydroxide ($Al(OH)_{3}$) is a base and hydrobromic acid (HBr) is a strong acid.

Hence an acid-base reaction occurs between $Al(OH)_{3}$ and HBr

Balanced molecular equation:

$Al(OH)_{3}(s)+3HBr(aq.)\rightarrow AlBr_{3}(aq.)+3H_{2}O(l)$

Balanced total ionic equation:

$Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)$

Balanced net ionic equation:

$Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)$

(net ionic equation is written by removing common ions present in both side of total ionic equation)