Six parallel-plate capacitors of identical plate separation have different plate areas a, different capacitances c, and differen
1 answer:
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<h3><u>Given :- </u></h3>
- Length of the rectangular wire, L=0.3 m
- Width of the rectangular wire, b=0.2m
- Magnetic field strength, B=0.8 T
- Velocity of the loop, v =12 m/s
- Induced Current, I = 3 A
(I) Emf developed,E in the loop is given as:
I = E/R
R = E/I
where
- R = resistance
- E = Induced EMF
- I = Current
(ii) The direction of current induced is from P to Q which is given by B × V vector . It may also be explained by Lenz law. Since magnetic field is from S to N . The fingers of the right hand are placed around the wire so that the curling of fingers will show the direction of the magnetic field produced by the wire then the thumb points in the direction of current flow which is from P to Q.
Answer:
Q = 29.4 x 10⁻⁹ C.
Explanation:
Electric field due to a charge Q at distance d is given by coulomb law as follows
Electric field
E = k Q /d²
where for air k which is a constant is 9 x 10⁹
Given E = 32.08 , d = 2.84 m
Putting these values in the relation above, we have
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Q = 29.4 x 10⁻⁹ C.