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Maru [420]
2 years ago
6

Explain other learning or ideas you gained about conservation of energy

Physics
1 answer:
Sav [38]2 years ago
4 0

Answer:

It can help individuals understand concepts such as the water-energy nexus and how water and energy work together to create a higher quality of life. Smart Energy Education teaches students about renewable energy, energy conservation, and the importance of energy as we transition into the future.

<em>8 Easy Ways for Kids to Conserve Energy at Home and School</em>

Take a Shower Instead of a Bath. ...

Limit Electronic Usage. ...

Turn Everything off When You Aren't in the Room. ...

Keep Windows and Blinds Closed. ...

Plant a Tree. ...

Ride a Bike or Walk to School. ...

Use Both Sides of a Piece of Paper. ...

Use a Reusable Water Bottle.

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a pitcher throws a 0.35 kg ball, giving it an acceleration of 10.0 m/s. what would the acceleration be, if the pitcher threw the
german

Answer:

New acceleration is 20.0 m/s².

Explanation:

F = m*a

F = 0.35 kg * 10.0m/s²

If Force will be doubled , and mass will be the same

we can write

2F = 2*0.35 kg*10.0 m/s²=0.35kg*20.0m/s²

New acceleration is 20.0 m/s².

8 0
4 years ago
1. After a rabbit population reaches the carrying capacity of its habitat, what will most likely happen to
kifflom [539]
C) alternately increase and decrease
6 0
3 years ago
Which part of the eye controls whether or not the pupil dilates or constricts? iris retina optic nerve cornea
Bas_tet [7]
The answer is Iris (i just took the quiz)
6 0
3 years ago
Read 2 more answers
Calcular el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones
sdas [7]

Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N

b)

F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N

c)

F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N

7 0
3 years ago
A 234.0 g piece of lead is heated to 86.0oC and then dropped into a calorimeter containing 611.0 g of water that initally is at
Vaselesa [24]

Answer:24.70 ^{\circ}C

Explanation:

Given

mass of lead piece m_l=234 gm\approx 0.234 kg

mass of water in calorimeter m_w=611 gm\approx 0.611 kg

Initial temperature of water T_w=24^{\circ}C

Initial temperature of lead piece T_l=24^{\circ}C

we know heat capacity of lead and water are 125.604 J/kg-k and 4.184 kJ/kg-k respectively

Let us take T ^{\circ}C be the final temperature of the system

Conserving energy

heat lost by lead=heat gained by water

m_lc_l(T_l-T)=m_wc_w(T-T_w)

0.234\times 125.604(86-T)=0.611\times 4.184\times 1000(T-24)

86-T=\frac{0.611\times 4.184\times 1000}{29.391}(T-24)

86-T=86.97T-2087.49

T=\frac{2173.491}{87.97}=24.70^{\circ}C

3 0
3 years ago
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