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3 years ago

HELP!!!!What is the area of `DeltaSTR`?

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

6 0

Answer: 27.7

Step-by-step explanation:

marta [7]3 years ago

5 0

Answer:

The answer to your question is: Area = 30 ft²

Step-by-step explanation:

Data

Right triangle

base = 6 ft

height = 10 ft

hypothenuse = 11.7 ft

Area = (base x height) / 2

Process

Area = (6 x 10) / 2

Area = 60/2

Area = 30 ft²

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If a bed costs £33 in the sale with 25% off what was the price before

Volgvan

I would like to say 44, but Im not positive.
But, 44x25% would equal 11. And 44-11(aka 25%) would equal 33.

You may want to double check my work though. Hope this helps

6 0

4 years ago

5(-6+4) distributive

Masteriza [31]

Answer:

-10

Step-by-step explanation:

5*-6=-30

5*4=20

-30+20=-10

8 0

4 years ago

Read 2 more answers

Suppose a shipment of 140 electronic components contains 3 defective components. to determine whether the shipment should be ac

MA_775_DIABLO [31]

The chance that one of the defective components is $\frac{3}{140}$ or 2.14285714% that the qc person will test a defective unit.

4 0

3 years ago

Read 2 more answers

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

Gelneren [198K]

Answer:

$v_2 \approx 1.12246\ m.s^{-1}$

$v_{10}\approx 1.4678\ m.s^{-1}$

$v_{100}\approx 1.4678\ m.s^{-1}$

Step-by-step explanation:

Mass of particles that a river can transport, $m\propto\ v^6$

where:

v = velocity of river flow

When $v=1\ m.s$

then the mass transported, $m \propto 1^6$

When mass is twice:

$v=\sqrt[6]{2}$

$v_2 \approx 1.12246\ m.s^{-1}$

When mass is 10 times:

$v=\sqrt[6]{10}$

$v_{10}\approx 1.4678\ m.s^{-1}$

When mass is 100 times:

$v=\sqrt[6]{100}$

$v_{100}\approx 1.4678\ m.s^{-1}$

7 0

3 years ago

How would you do number 12 and 15?

Gnesinka [82]

Answer:

$x_1=x_2=-\dfrac{2}{3}$

Step-by-step explanation:

For the quadratic equation $ax^2+bx+c=0$ the discriminant is defined as

$D=b^2-4ac$

and the quadratic formula for the roots gives us two roots:

$x_1=\dfrac{-b-\sqrt{D}}{2a}$

and

$x_2=\dfrac{-b+\sqrt{D}}{2a}$

For the equation $9x^2 +12x+4=0$ use quadratic formula to find roots:

$D=12^2-4\cdot 9\cdot 4=144-144=0$

So,

$x_1=x_2=\dfrac{-12\pm \sqrt{0}}{2\cdot 9}=-\dfrac{12}{18}=-\dfrac{2}{3}$

7 0

4 years ago