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Kisachek [45]
3 years ago
12

What is an equation in point-slope form for the line that passes through the points (−3,5) and (2,−3)?

Mathematics
1 answer:
fredd [130]3 years ago
4 0
(-3,5). (2,-3)
x1,y1. x2,y2

y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1

plug the rest in

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<img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%5Clim_%7Bx%20%5Cto%200%20%7D%20%5Cfrac%7B1%20-%20%5Cprod%20%5Climits_%
xxTIMURxx [149]

To demonstrate a method for computing the limit itself, let's pick a small value of n. If n = 3, then our limit is

\displaystyle \lim_{x \to 0 } \frac{1 - \prod \limits_{k = 2}^{3} \sqrt[k]{\cos(kx)} }{ {x}^{2} }

Let a = 1 and b the cosine product, and write them as

\dfrac{a - b}{x^2}

with

b = \sqrt{\cos(2x)} \sqrt[3]{\cos(3x)} = \sqrt[6]{\cos^3(2x)} \sqrt[6]{\cos^2(3x)} = \left(\cos^3(2x) \cos^2(3x)\right)^{\frac16}

Now we use the identity

a^n-b^n = (a-b)\left(a^{n-1}+a^{n-2}b+a^{n-3}b^2+\cdots a^2b^{n-3}+ab^{n-2}+b^{n-1}\right)

to rationalize the numerator. This gives

\displaystyle \frac{a^6-b^6}{x^2 \left(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5\right)}

As x approaches 0, both a and b approach 1, so the polynomial in a and b in the denominator approaches 6, and our original limit reduces to

\displaystyle \frac16 \lim_{x\to0} \frac{1-\cos^3(2x)\cos^2(3x)}{x^2}

For the remaining limit, use the Taylor expansion for cos(x) :

\cos(x) = 1 - \dfrac{x^2}2 + \mathcal{O}(x^4)

where \mathcal{O}(x^4) essentially means that all the other terms in the expansion grow as quickly as or faster than x⁴; in other words, the expansion behaves asymptotically like x⁴. As x approaches 0, all these terms go to 0 as well.

Then

\displaystyle \cos^3(2x) \cos^2(3x) = \left(1 - 2x^2\right)^3 \left(1 - \frac{9x^2}2\right)^2

\displaystyle \cos^3(2x) \cos^2(3x) = \left(1 - 6x^2 + 12x^4 - 8x^6\right) \left(1 - 9x^2 + \frac{81x^4}4\right)

\displaystyle \cos^3(2x) \cos^2(3x) = 1 - 15x^2 + \mathcal{O}(x^4)

so in our limit, the constant terms cancel, and the asymptotic terms go to 0, and we end up with

\displaystyle \frac16 \lim_{x\to0} \frac{15x^2}{x^2} = \frac{15}6 = \frac52

Unfortunately, this doesn't agree with the limit we want, so n ≠ 3. But you can try applying this method for larger n, or computing a more general result.

Edit: some scratch work suggests the limit is 10 for n = 6.

6 0
2 years ago
Summer exercises for 0.5 hour on Monday Wednesday and Friday each week. How many hours will she exercise in four weeks
Sati [7]

Answer:

She will exercise for 6 hours in four weeks.

Step-by-step explanation:

Summer exercises for 0.5 hour on Monday, 0.5 hour on Wednesday, and 0.5 hour on Friday. There are 3 days where she exercises for 0.5 hour.

3 days X 0.5h = 1.5h each week

For four weeks, multiply the hours each week by 4.

1.5h X 4 weeks = 6h

Therefore Summer will exercise for 6 hours over the course of 4 weeks.

6 0
3 years ago
Read 2 more answers
(7y^6z^4-4y^2)(-6yz^4)
rosijanka [135]
I dont lnow the awnser of that but good luck on that!
7 0
3 years ago
Write the expression nine divided by the quantity of x plus y
seropon [69]

9514 1404 393

Answer:

  \text{A)}\quad\dfrac{9}{x+y}

Step-by-step explanation:

In the English expression, you need to understand that "A divided by B" means that A is the numerator and B is the denominator of the fraction representing the division. Here, "B" is "the quantity of ...", which means that the stuff after "of ..." is to be treated as a single item, the denominator in this case. That item is "x plus y." So, the expression in math terms is ...

  \dfrac{9}{x+y}

When this is written in plain text, the "quantity" is put in parentheses, because the fraction bar no longer serves as a grouping symbol:

  9/(x+y)

These expressions match the first choice, A.

7 0
3 years ago
A line with a slope of 10 passes through the point (0,4). What is its equation in
Alexus [3.1K]

Answer:

y=10x+4

Step-by-step explanation:

y-y1=m(x-x1)

y-4=10(x-0)

y-4=10(x)

y-4=10x

y=10x+4

7 0
2 years ago
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