Two workers, if they were working together, could finish a certain job in 12 days. If one of the workers does the first half of
2 answers:
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The answer is 
![\sqrt[3]{ \frac{ a^{6} b^{9} }{-64} } = \frac{ \sqrt[3]{a^{6} b^{9}} }{ \sqrt[3]{-64} } = \frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B%20a%5E%7B6%7D%20b%5E%7B9%7D%20%20%7D%7B-64%7D%20%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%20b%5E%7B9%7D%7D%20%7D%7B%20%20%5Csqrt%5B3%5D%7B-64%7D%20%20%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B%20b%5E%7B9%7D%7D%20%7D%7B%20%20%5Csqrt%5B3%5D%7B-64%7D%7D%20)
Since (xᵃ)ᵇ = xᵃ*ᵇ, then:
a⁶ = (a²)³
b⁹ = (b³)³
Also: 64 = 4³
![\frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}= \frac{ \sqrt[3]{( a^{2})^{3} }*\sqrt[3]{( b^{3})^{3} } }{\sqrt[3]{( -4)^{3} }} = \frac{ a^{2} * b^{3} }{-4}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B%20b%5E%7B9%7D%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B-64%7D%7D%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B%28%20a%5E%7B2%7D%29%5E%7B3%7D%20%7D%2A%5Csqrt%5B3%5D%7B%28%20b%5E%7B3%7D%29%5E%7B3%7D%20%7D%20%7D%7B%5Csqrt%5B3%5D%7B%28%20-4%29%5E%7B3%7D%20%7D%7D%20%3D%20%5Cfrac%7B%20a%5E%7B2%7D%20%2A%20b%5E%7B3%7D%20%7D%7B-4%7D%20)
Since (xᵃ)ᵇ = xᵃ*ᵇ, then:
a⁶ = (a²)³
b⁹ = (b³)³
Also: 64 = 4³
Table-1 shows constant increase of X and Y values
Step-by-step explanation:
We are given two tables with X and Y values.
To find which table represent the constant increase of X and Y:
If there is constant increase of X and Y then, X and Y avlues belongs to equation of line.
Also, if three points lies on line then, slope of line made by three points must be same or equal.
Slope of line is given as s=
For table 1:
The values of X and Y form points as A(3,4),B(5,6) and C(7.8)
For A(3,4) and B(5,6)
s=
s=
s=1
For C(7.8) and B(5,6)
s=
s=
s=1
Therefore, Table-1 shows constant increase of X and Y values
For table 2:
The values of X and Y form points as A(1,3),B(2,6) and C(3,10)
For A(1,3) and B(2,6)
s=
s=
s=3
ForC(3,10) and B(5,6)
s=
s=
s=2
Therefore, Table-1 does not shows constant increase of X and Y values