Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18
<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
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Answer: k=9/4
Step-by-step explanation: We can do this by finding a number that adds up to 3 when multiplied by 2. The best way to do this is to use ((b^2)/4) which can usually find you the number for a perfect square based on b, which we have. So, 3^2 / 4 =9/4, meaning k=9/4. We can check:
>x^2 +3x +9/4
> (x+3/2)(x+3/2)
Perfect square.
I’ll answer this in a second
