I believe that would equal 65/21
hope that helps!
Answer:
The sum is 
Step-by-step explanation:
we have

we have



Find the common ratio r


The common ratio is r=6
The formula to calculate the sum in a geometric sequence is equal to

where
n is the number of terms
r is the common ratio
a1 is the first term
we have



substitute



Answer:
Step-by-step explanation:
Note that the cost function is
, which gives us the cost of electricity for x hours of consumption
a). The function ![c^{-1}(x)[tex] which is the inverse function, tells us given a cost, the amount of hours we can consume electricty. b) Consider the equation [tex]y=7.1+23\ln(x)](https://tex.z-dn.net/?f=c%5E%7B-1%7D%28x%29%5Btex%5D%20which%20is%20the%20inverse%20function%2C%20tells%20us%20given%20a%20cost%2C%20the%20amount%20of%20hours%20we%20can%20consume%20electricty.%20%3C%2Fp%3E%3Cp%3Eb%29%20Consider%20the%20equation%20%3C%2Fp%3E%3Cp%3E%5Btex%5Dy%3D7.1%2B23%5Cln%28x%29)
To find out the inverse function, we interchange the labels of x and y and solve for y, that is
when solved for y we have

So the inverse function is given by
.
c) We will use the inverse function to find the amount of hours the customer can use eelectricity. It is simple obtained by evaluating the inverse function at the desired cost (i.e
)
that is

that is, the custome can consume at most 1.41 hours of electricity.
The line passes through the x-axis at (-4,0) and there is no y-intercept.
Answer:
about 9.93 W
Step-by-step explanation:
The area of the sphere having a radius of 5 m is ...
A = 4πr² = 4π(5 m)² = 100π m² ≈ 314.16 m²
The sound intensity at that distance is ...
dB = 10·log(I/I0)
105 = 10·log(I/I0) . . . . substitute given values
10^10.5 = I/I0 . . . . divide by 10 and take the antilog
For such sound intensity measurements, the reference power level is ...
I0 = 10^-12 W/m²
Using this in the formula, we have ...
I = (10^10.5)·I0 = (10^10.5)·(10^-12 W/m²) = 10^-1.5 W/m²
Since the area of the sphere is 314.16 m², the total power of the siren is ...
(314.16 m²)(0.031623 W/m²) ≈ 9.93 W