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3 years ago

MathPhys May you help me once again?

Physics

1 answer:

Maru [420]3 years ago

6 0

Answer:

2. Same force; same impulse; Mini Cooper has greater change in velocity

4. Same momentum

6. It is distributed to the two halves

Explanation:

I will do the even problems as examples.

2. From Newton's third law, we know the bulldozer and Mini Cooper will experience equal but opposite forces. So the magnitude of the force is the same.

Impulse is force times time. Since the force is the same, and the amount of time is the same, then the impulse is the same.

Impulse is equal to change in momentum, or mass times change in velocity. Since the Mini Cooper has the smaller mass, it has the greater change in velocity.

4. Momentum is mass times velocity. The weight of the rover is different on Mars than on Earth, but the mass is still the same. Therefore, if the rover moves at the same speed, it will have the same momentum.

6. The pencil's momentum is conserved. When the pencil breaks in half, half the momentum goes to one half of the pencil, and half the momentum goes to the other half of the pencil.

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A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n=1) interfere

dalvyx [7]

Answer:

wavelength = 4 m

Explanation:

For distance 6 and 8m and speed of sound in air = c.

The travel time form the various distances 6 and 8 are 6/c and 8/c respectively.

cos(wt1) + cos(wt2) = 0

for a shift in phase t1 = t - 6/c,

t2 = t - 8/c

substituting t1 and t2

cos(π - w(t - 8/c)) = cos(w(t - 6/c))

solving using trigonometry identities in radians.

we have,

π - 2πn = w(t - 8/c) - w(t - 6/c)

putting w = 2πf

π - 2πn = 2πf(t - 8/c) - 2πf(t - 6/c)

dividing both sides by π

1 - 2n = 2ft - 16(f/c) - 2ft + 12(f/c)

simplifying we have,

1 - 2n = -4(f/c)

solving for f we have,

f = c/4(2n - 1)

putting n=1 and c = 343m/s

f = (343/4)*(2(1) - 1)

f = 85.75 Hertz

wave lenght = c/f , where c= speed of sound in air , f= frequency

wave lenght = 343/85.75 = 4m

5 0

3 years ago

A bar magnet is immersed in a heap of iron fillings and pulled out . The amount of iron fillings clinging to the ?

grin007 [14]

Answer:

North Pole is almost equal to the South Pole.

Explanation:

The magnetic fields are weaker in the center of a magnet than at the poles. Poles have the maximum magnetic strength of equal intensity. When dipped in a heap of iron fillings, the fillings gets attracted to the poles than other parts of magnet. Therefore, the amount of iron fillings attracted to both the poles will be almost equal.

<em>Hope this helps</em>

8 0

3 years ago

Which of the substances in the chart has the greatest density?

svlad2 [7]

A.gold is the answer. As it's density is 19.32 grams per cubic centimeter which is lot more than the other substances.

4 0

3 years ago

A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°. what is the horizontal component of the

stepan [7]

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)· $\hat i$ + 21 × sin(51°)· $\hat j$

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.

3 0

4 years ago

ASK YOUR TEACHER A 2.0-kg mass swings at the end of a light string with the length of 3.0 m. Its speed at the lowest point on it

Nadya [2.5K]

Answer:

K_b = 78 J

Explanation:

For this exercise we can use the conservation of energy relations

starting point. Lowest of the trajectory

Em₀ = K = ½ mv²

final point. When it is at tea = 50º

Em_f = K + U

Em_f = ½ m v_b² + m g h

where h is the height from the lowest point

h = L - L cos 50

Em_f = ½ m v_b² + mg L (1 - cos50)

energy be conserve

Em₀ = Em_f

½ mv² = ½ m v_b² + mg L (1 - cos50)

K_b = ½ m v_b² + mg L (1 - cos50)

let's calculate

K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)

K_b = 36 +42.0

K_b = 78 J

4 0

3 years ago