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Yuki888 [10]
3 years ago
12

Three forces are exerted on an object placed on a slope in the figure. The forces are measured in Newton (N).

Physics
2 answers:
kobusy [5.1K]3 years ago
4 0

Answer:

1. Component = F - mgsin\theta - \mu R

2. Normal

3. F_{up} - F_{friction}

4 . upwards

Explanation:

1. The diagram on a slope shows the forces acting on an object. There a three sets of forces that are on the object. One is the normal force, N. The other one is the pulling force, which shall be called .

The last component is the force acting on the object due to friction. this is given as F_{total}  = mgsin\theta

2. The perpendicular force is the normal. It is given as N

3. The magnitude of the Fnet is the difference in all the forces.

4. Overall, the net force will be upwards as the object is being pulled in that direction.

Vika [28.1K]3 years ago
3 0
<span>The component of the net force that is parallel to the slope is the friction force. It is the force due to the friction present between the object and the surface of the slope. The force perpendicular to the slope is called the normal force and it is the contact force exerted by the object to the surface of the slope.</span>
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Answer:

The minimum possible coefficient of static friction between the tires and the ground is 0.64.

Explanation:

if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :

Fc = f

m×(v^2)/(R) = μ×m×g

    (v^2)/(R) = g×μ

               μ = (v^2)/(R×g)

                  =  ((25)^2)/((100)×(9.8))

                  = 0.64

Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.

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3 years ago
What characteristics distinguish the inner planets in the solar system from the outer planets?
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Explanation:

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2 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 29.4 m/s2 m /
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Answer:

The maximum height is 2881.2 m.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 7.00 s

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Using equation of motion

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Put the value into the formula

s=0+\dfrac{1}{2}\times29.4\times7^2

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Using formula of velocity

v=a\times t

Put the value into the formula

v=29.4\times7

v=205.8\ m/s

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Using formula of height

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Put the value into the formula

H=\dfrac{(205.8)^2}{2\times9.8}

H=2160.9\ m

We need to calculate the maximum height

Using formula for maximum height

H'=H+s

Put the value into the formula

H'=2160.9+720.3

H'=2881.2\ m

Hence, The maximum height is 2881.2 m.

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Nresistors, each having resistance equal to 1 2, are arranged in a circuit first in series and then in parallel. What is the rat
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Answer:

option (b)

Explanation:

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Ps = v^2 / Rs = V^2 / NR ..... (1)

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Power is parallel

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