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Yuki888 [10]
3 years ago
12

Three forces are exerted on an object placed on a slope in the figure. The forces are measured in Newton (N).

Physics
2 answers:
kobusy [5.1K]3 years ago
4 0

Answer:

1. Component = F - mgsin\theta - \mu R

2. Normal

3. F_{up} - F_{friction}

4 . upwards

Explanation:

1. The diagram on a slope shows the forces acting on an object. There a three sets of forces that are on the object. One is the normal force, N. The other one is the pulling force, which shall be called .

The last component is the force acting on the object due to friction. this is given as F_{total}  = mgsin\theta

2. The perpendicular force is the normal. It is given as N

3. The magnitude of the Fnet is the difference in all the forces.

4. Overall, the net force will be upwards as the object is being pulled in that direction.

Vika [28.1K]3 years ago
3 0
<span>The component of the net force that is parallel to the slope is the friction force. It is the force due to the friction present between the object and the surface of the slope. The force perpendicular to the slope is called the normal force and it is the contact force exerted by the object to the surface of the slope.</span>
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Answer:

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What is the passenger's apparent weight at t=1.0s?
Fittoniya [83]

Answer:

For the complete question provided in explanation, if the elevator moves upward, then the apparent weight will be 1035 N. While for downward motion the apparent weight will be 435 N.

Explanation:

The question is incomplete. The complete question contains a velocity graph provided in the attachment. This is the velocity graph for an elevator having a passenger of 75 kg.

From the slope of graph it is clear that acceleration at t = 1 sec is given as:

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