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Lapatulllka [165]
1 year ago
13

The quartz crystal in a digital watch has a frequency of 32. 8 khz. what is its period of oscillation?

Physics
2 answers:
JulijaS [17]1 year ago
8 0

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

Two related parameters are oscillation frequency and period. Actually, they are the opposites of one another. As a result, the following formula can be used to determine the quartz crystal's oscillation period:

Time Period of Oscillation = 1/Oscillation Frequency

where.

Frequency of Oscillation-32.8 KHz

Frequency of Oscillation - 32800 H₂

Therefore

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

learn more about Oscillation brainly.com/question/12622728

#4256

strojnjashka [21]1 year ago
3 0

The time period of oscillation is 3.04×10

what is time period?

A time period (denoted by 'T'' ) is the time taken for one complete cycle of vibration to pass a given point.[1] As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds'.

The related parameters are oscillation frequency and period.They are the opposite of the another.As a result the formula to be used is

frequency=1/time

given:

Frequency of oscillation=32.8khz=32800hz

therefore,

time period of oscillation=1/32800hz

time period of oscillation=3.04×10

learn more about oscillation from here: brainly.com/question/28167898

#SPJ4

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Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it trie
sammy [17]

Answer:

2.64 m/s

Explanation:

Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna

Momentum = MV

Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s

Momentum of the tun final before collision = 100 × 0.5 = 50 kgm/s

Total momentum before collision = 1800 + 50 = 1850 kgm/s

Let's assume that they move together after collision. Then,

1850 = ( 600 + 100 ) V

1850 = 700V

V = 1850 / 700

V = 2.64285 m/s

Therefore, the momentum of the shark after collision is 2.64 m/ s approximately

6 0
3 years ago
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Andrew [12]
The last one, the soil will become weak & unable to support plant growth
4 0
3 years ago
A 2.1 kg block is dropped from rest from a height of 5.5 m above the top of the spring. When the block is momentarily at rest, t
ella [17]

Answer:

The speed of the block is 8.2 m/s

Explanation:

Given;

mass of block, m = 2.1 kg

height above the top of the spring, h = 5.5 m

First, we determine the spring constant based on the principle of conservation of potential energy

¹/₂Kx² = mg(h +x)

¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)

0.03125K = 118.335

K = 118.335 / 0.03125

K = 3786.72 N/m

Total energy stored in the block at rest is only potential energy given as:

E = U = mgh

U = 2.1 x 9.8 x 5.5 = 113.19 J

Work done in compressing the spring to 15.0 cm:

W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J

This is equal to elastic potential energy stored in the spring,

Then, kinetic energy of the spring is given as:

K.E = E - W

K.E = 113.19 J - 42.6 J

K.E = 70.59 J

To determine the speed of the block due to this energy:

KE =  ¹/₂mv²

70.59 =  ¹/₂ x 2.1 x v²

70.59 = 1.05v²

v² = 70.59 / 1.05

v² = 67.229

v = √67.229

v = 8.2 m/s

8 0
3 years ago
Read 2 more answers
78 million in standard form
Leviafan [203]

Answer:

78 million in standard form is 78,000,000

6 0
3 years ago
During a thunderstorm a tornado lift a car to a height of 300 m above the ground increasing and strength the tornado flings the
sasho [114]

Answer:

Explanation:

To calculate the time it took the car to hit the ground, we use the formula

speed = distance/time

80 m/s = 300 m/time

time = 300/80

time = 3.75 secs

It must have taken the car 3.75 seconds to hit the ground

To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)

speed = distance/time

80 = distance/3.75

distance = 3.75 x 80

distance = 300 meters

4 0
2 years ago
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