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Lapatulllka [165]
1 year ago
13

The quartz crystal in a digital watch has a frequency of 32. 8 khz. what is its period of oscillation?

Physics
2 answers:
JulijaS [17]1 year ago
8 0

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

Two related parameters are oscillation frequency and period. Actually, they are the opposites of one another. As a result, the following formula can be used to determine the quartz crystal's oscillation period:

Time Period of Oscillation = 1/Oscillation Frequency

where.

Frequency of Oscillation-32.8 KHz

Frequency of Oscillation - 32800 H₂

Therefore

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

learn more about Oscillation brainly.com/question/12622728

#4256

strojnjashka [21]1 year ago
3 0

The time period of oscillation is 3.04×10

what is time period?

A time period (denoted by 'T'' ) is the time taken for one complete cycle of vibration to pass a given point.[1] As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds'.

The related parameters are oscillation frequency and period.They are the opposite of the another.As a result the formula to be used is

frequency=1/time

given:

Frequency of oscillation=32.8khz=32800hz

therefore,

time period of oscillation=1/32800hz

time period of oscillation=3.04×10

learn more about oscillation from here: brainly.com/question/28167898

#SPJ4

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Yanka [14]

"Fig is attacted with answer"

Answer:

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Explanation:

a)

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Given data:

time = t = 4.00 s

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Horizontal distance = d = ?

Using 2nd  equation of motion

h = v_{y_{f}}t + \frac{1}{2}gt^{2}

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b)

We know the values of Landing angle, height of roof, time of flight. In part a, We calculate the landing velocity of the ball and also its horizontal and vertical component. As the ball followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

So,

v_{x_{f}} = v_{x_{i}}

but the vertical component of velocity vary with and there is an acceleration along vertical direction which is equal to gravitation acceleration g.

So,

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c)

cos β = v_{x_{i}} / v_{i}

β = cos⁻¹ (8.43 / 26)

β = 71.08°

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