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Lapatulllka [165]
1 year ago
13

The quartz crystal in a digital watch has a frequency of 32. 8 khz. what is its period of oscillation?

Physics
2 answers:
JulijaS [17]1 year ago
8 0

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

Two related parameters are oscillation frequency and period. Actually, they are the opposites of one another. As a result, the following formula can be used to determine the quartz crystal's oscillation period:

Time Period of Oscillation = 1/Oscillation Frequency

where.

Frequency of Oscillation-32.8 KHz

Frequency of Oscillation - 32800 H₂

Therefore

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

learn more about Oscillation brainly.com/question/12622728

#4256

strojnjashka [21]1 year ago
3 0

The time period of oscillation is 3.04×10

what is time period?

A time period (denoted by 'T'' ) is the time taken for one complete cycle of vibration to pass a given point.[1] As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds'.

The related parameters are oscillation frequency and period.They are the opposite of the another.As a result the formula to be used is

frequency=1/time

given:

Frequency of oscillation=32.8khz=32800hz

therefore,

time period of oscillation=1/32800hz

time period of oscillation=3.04×10

learn more about oscillation from here: brainly.com/question/28167898

#SPJ4

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Explanation:

Let's begin by explaining that according to Kepler’s Third Law of Planetary motion “The square of the orbital period T of a planet is proportional to the cube of the semi-major axis a of its orbit”:

T^{2}\propto a^{3} (1)  

Now, if T is measured in years (Earth years), and a is measured in astronomical units (equivalent to the distance between the Sun and the Earth: 1AU=1.5(10)^{8}km), equation (1) becomes:  

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So, knowing T=619.36 years and isolating a from (2) we have:  

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a=72.66 AU T his is the distance between the dwarf planet and the Sun in astronomical units

Converting this to kilometers, we have:

a=72.66 AU \frac{1.5(10)^{8}km}{1 AU}=1.089(10)^{10} km

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