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Lapatulllka [165]
1 year ago
13

The quartz crystal in a digital watch has a frequency of 32. 8 khz. what is its period of oscillation?

Physics
2 answers:
JulijaS [17]1 year ago
8 0

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

Two related parameters are oscillation frequency and period. Actually, they are the opposites of one another. As a result, the following formula can be used to determine the quartz crystal's oscillation period:

Time Period of Oscillation = 1/Oscillation Frequency

where.

Frequency of Oscillation-32.8 KHz

Frequency of Oscillation - 32800 H₂

Therefore

Time Period of Oscillation-1/32800 Hz

Time Period of Oscillation - 3.04 × 10¹.

learn more about Oscillation brainly.com/question/12622728

#4256

strojnjashka [21]1 year ago
3 0

The time period of oscillation is 3.04×10

what is time period?

A time period (denoted by 'T'' ) is the time taken for one complete cycle of vibration to pass a given point.[1] As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds'.

The related parameters are oscillation frequency and period.They are the opposite of the another.As a result the formula to be used is

frequency=1/time

given:

Frequency of oscillation=32.8khz=32800hz

therefore,

time period of oscillation=1/32800hz

time period of oscillation=3.04×10

learn more about oscillation from here: brainly.com/question/28167898

#SPJ4

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Answer:

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Explanation:

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2

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We have to find the speed of the wave in the string

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Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object m_1=52 kg

distance of m_1 from the axle r_1=14 cm

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Where \theta =angle\ turned =\frac{\pi }{2}

v= velocity\ at\ launch

66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}

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Explanation:

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