Finding out the acceleration 12/3 = 4m/s^2
thus it is descending so the actual acceleration would be 9.8-4 = 5.8 m/s^2
the weight will be 90*5.8 = 522 N
522/9.8 = 53.2 kg
Your answer is correct. No problem and Have a nice day
Answer:
Total distance, ![d=\dfrac{xyt}{(x+y)}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bxyt%7D%7B%28x%2By%29%7D)
Explanation:
It is given that,
Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.
We he moves from home to destination, time is equal to, ![\dfrac{d}{x}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bx%7D)
Similarly, when he move back to home, time taken is equal to ![\dfrac{d}{y}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7By%7D)
Total time taken is equal to :
![\dfrac{d}{x}+\dfrac{d}{y}=t](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bx%7D%2B%5Cdfrac%7Bd%7D%7By%7D%3Dt)
![d(\dfrac{1}{x}+\dfrac{1}{y})=t](https://tex.z-dn.net/?f=d%28%5Cdfrac%7B1%7D%7Bx%7D%2B%5Cdfrac%7B1%7D%7By%7D%29%3Dt)
![d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bt%7D%7B%28%5Cdfrac%7B1%7D%7Bx%7D%2B%5Cdfrac%7B1%7D%7By%7D%29%7D)
![d=\dfrac{xyt}{(x+y)}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bxyt%7D%7B%28x%2By%29%7D)
So, the distance he speed in walking and jogging is
. Hence, this is the required solution.
Answer: Option (D) is the correct answer.
Explanation:
A chemical reaction is defined as the reaction which causes change in chemical composition of a substance.
According to law of conservation of mass, mass can neither be created nor it can be destroyed. It can only be changed from one form to another.
For example, ![H^{+} + Cl^{-} \rightarrow HCl](https://tex.z-dn.net/?f=H%5E%7B%2B%7D%20%2B%20Cl%5E%7B-%7D%20%5Crightarrow%20HCl)
Here, total mass of reactants = (1.008 + 35.453) g/mol = 36.461 g/mol
Whereas total mass of products = 36.461 g/mol
This shows that mass remains the same before or after the reaction.
Similarly, the number of atoms of the type involved will remains the same as no change in their nucleus is occurring.
Thus, we can conclude that the following must be the same before and after a chemical reaction.
- The sum of the masses of all substances involved.
- The number of atoms of the type involved.