The density (d) of a substance is calculated by dividing the mass (m) by the given volume (v). Mathematically,
d = m / v
Substituting the known values,
d = 374 g / (2.2 x 10^3 L) = 0.17 g/L
Thus, the density of the weather balloon is 0.17 g/L.
Answer:
v = 2917.35 m/s
Explanation:
let Fc be the centripetal force avting on the satelite , Fg is the gravitational force between mars and the satelite, m is the mass of the satelite and M is the mass of mars.
at any point in the orbit the forces acting on the satelite are balanced such that:
Fc = Fg
mv^2/r = GmM/r^2
v^2 = GM/r
v = \sqrt{GM/r}
= \sqrt{(6.6708×10^-11)(6.38×10^23)/(3.38×10^6 + 1.62×10^6)}
= 2917.35 m/s
Therefore, the orbital velocity of the satelite orbiting mars is 2917.35 m/s.
The speed of the electron when it is 10.0 cm from the +3.00 nC charge is 30× meters per second.
Given :
q=3.00 nC
r=distance=10 c.m
we apply formula
Velocity of electron =qd
=10××3=30× m/sec
The speed of electricity is determined by what you mean by the term "electricity." This is a broad term that essentially means "all things relating to electric charge." I'll presume we're talking about an electrical charge current moving through a metal wire, like the power cord of a light. Electrical currents passing through metal wires have three different velocities, all of which are physically significant:
The velocity of electron drift.
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The force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
<h3>Force of the object</h3>
F = mv/t
where;
- m is mass of the object = 200 kg
- v is velocity of the object = 60 m/s
- t is time of motion = 5 mins = 300 seconds
F = (200 x 60)/(300)
F = 40 N
<h3>Velocity of the object</h3>
F = mv/t
Ft = mv
v = Ft/m
where;
- m is mass = 600 kg
- F is force = 150 N
- t is time = 2 mins = 120 s
v = (150 x 120)/(600)
v = 30 m/s
Thus, the force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
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Answer:
The height from which the rock was thrown is 1.92 m
Solution:
As per the question:
Speed with which the rock is thrown, v = 12.0 m/s
Horizontal distance traveled by the rock before it hits the ground, d = 15.5 m
Launch angle,
Now,
To calculate the height, h from which the rock was thrown:
First, since we consider the horizontal motion in the trajectory of the rock, thus the time taken is given by:
Now,
The height from which the rock was thrown is given by the kinematic eqn, acceleration in the horizontal direction is zero: