Jamaljajajjajsjsjjejdjdnjdisijsjsjejwoiw
        
             
        
        
        
Answer
given,
mass of block = m = 2.3 Kg
spring constant = k = 150 N/m
speed = 2.3 m/s
a) we know,
    
    
              ω = 8.08 rad/s
       v = A ω
       2.3 = A x 8.08 
          A = 0.285 m
b) maximum acceleration
         a = A ω²
         a = 0.285 x 8.08²
          a = 18.58 m/s²
c) acceleration is minimum at mean position the minimum value of acceleration is zero.
d) time period 
    
    
             T = 0.778 s
         t = 4.1 x 0.7778
         t = 3.188 s
 
        
             
        
        
        
Answer:
Explanation:
 ![r^2 = [\frac{l}{2}]^2 +[\frac{l}{2}]^2](https://tex.z-dn.net/?f=r%5E2%20%3D%20%5B%5Cfrac%7Bl%7D%7B2%7D%5D%5E2%20%2B%5B%5Cfrac%7Bl%7D%7B2%7D%5D%5E2)


we know that electric field is given as

from the figure electric field c and electric field a CANCEL OUT EACH OTHER
so, we have E_B and E_D is toward -q direction





 
        
             
        
        
        
Average velocity is different than average speed because calculating average velocity involves Momentum.