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natima [27]
3 years ago
9

A weightlifter expends 294 w of power lifting a weight to a height of 2 m in 10 seconds. what mass has he lifted?

Physics
1 answer:
Masja [62]3 years ago
3 0
The power of the weightlifter is equal to the ratio between the work done by it and the time taken:
P= \frac{W}{t}
since we know the power and the time, we can find the work done:
W=Pt=(294 W)(10 s)=2940 J

For the work-energy theorem, this work done by the lifter is equal to the gravitational potential energy gained by the mass, which is given by:
U=mg \Delta h
where m is the mass and \Delta h is the increase in height. Rearranging the formula and using W=U, we can find the mass:
m= \frac{U}{g\Delta h}= \frac{2940 J}{(9.81 m/s^2)(2 m)}=149.8 kg
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Se tienen 500g de alcohol etílico a una temperatura de -40 °C ¿Cuánto calor se necesita para transformarlo a vapor a una tempera
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The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?

Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

Explanation:

Given: Mass = 500 g

Initial temperature = -40^{o}C

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The standard value of specific heat of ethyl alcohol is 2.46 J/g ^{o}C.

Formula used to calculate the heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

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Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J

Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

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