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2 years ago

Answer This!!!!!! I'll give brainliest to whoever gets it right. And 100 Points!

Physics

1 answer:

n200080 [17]2 years ago

6 0

Answer: Time (days) = 88, the (mass) = 0.2180

Explanation:

Time (days) = 88, the (mass) = 0.2180

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What is one standard kilogramun si system

Phoenix [80]

Answer:

The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.

3 0

3 years ago

Read 2 more answers

An instrument that measures air pressure using a partially evacuated chamber is called a(n ________ barometer.

Jet001 [13]

The appropriate response is the Aneroid barometer. This kind of gauge has an incompletely cleared chamber that progressions shape, packing as barometrical weight increments and growing as weight declines.

I hope the answer will help you.

6 0

3 years ago

If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?

Aliun [14]

Answer:

F = G Newtons

Explanation:

Given:

Mass of 1st body = $1\:kg$
Mass of 2nd body = $4\:kg$

To Find:

Magnitude of gravitational force

Solution:

Here, we have a formula

$F=\dfrac{G.M_{1}.M_{2}}{r^{2}}$

Substituting the values

$\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}$

$\implies\:\:F = \dfrac{4G}{4}$

$\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}$

$\implies\:\:\red{F = G}$

Know More:

The applied formula for the above solution is

${\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}$

where,

F $_{G}$ = Gravitational force
G = Gravitational constant
M $_{1}$ = mass of 1st body
M $_{2}$ = mass of 2nd body
r = distance between two bodies

6 0

3 years ago

At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in

bearhunter [10]

Answer:

$P = 1.09 \times 10^8 Pa$

Explanation:

As we know that the pressure inside the liquid level is given as

$P = \rho g h + P_o$

here we have

$\rho = 1024 kg/m^3$

h = 10.9 km

also we know that

$P_o = 1.01 \times 10^5 Pa$

now we have

$P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)$

$P = 1.09 \times 10^8 Pa$

8 0

3 years ago

the weight of a body is more at polar regions of the earth than that at the equatorial regions? why give reason

ella [17]

Answer:

The weight of an object at the Earth's South Pole is slightly more than its weight at the Equator because the polar radius of the Earth is slightly less than the equatorial radius. Though the mass of an object remains constant, its weight varies according to its location.

Explanation:

3 0

3 years ago