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antiseptic1488 [7]
3 years ago
5

1.do materials change when light is reflected off to them

Physics
2 answers:
hodyreva [135]3 years ago
7 0
Number two) C. Maybe
Natalka [10]3 years ago
3 0
I’m not certain but 1 i think is yes or maybe but it’s definitely not no
2 is no because when light passes through materials the speed changes and the light reflects and refracts from it 3 is yes i think
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a truck is moving around a circular curve @ a uniform velocity of 13m/s. if the centifrical force on truck is 3,300N with truck
VMariaS [17]

<u>Answer</u>

81.94 m


<u>Explanation</u>

The centripetal force of an object moving in a circular path is given by:

F = mv²/r  Where m is the mass of the object, v is the constant velocity and r is the radius of the curve.

F = mv²/r

3,300 = (1600×13²)/r

3,300 = 270,400/r

r = 270,400/3,300

  = 81.94 m

8 0
3 years ago
Which waves are used in medicine?
Reika [66]

Answer:

C

Explanation:

4 0
3 years ago
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point
Salsk061 [2.6K]

Answer:

The fluids speed at a) 0.105\,m^{2}  and b) 0.047\,m^{2} are 2.33\,\frac{m}{s^{2}}  and 5.21\,\frac{m}{s^{2}} respectively

c) Th volume of water the pipe discharges is: 882\,m^{3}  

Explanation:

To solve a) and b) we should use flow continuity for ideal fluids:

\Delta Q=0(1)

With Q the flux of water, but Q is Av using this on (1) we have:

A_{2}v_{2}-A_{1}v_{1}=0 (2)

With A the cross sectional areas and v the velocities of the fluid.

a) Here, we use that point 2 has a cross-sectional area equal to A_{2}=0.105\,m^{2}, so now we can solve (2) for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.105}\approx2.33\,\frac{m}{s^{2}}

b) Here we use point 2 as A_{2}=0.047\,m^{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}}=\frac{(0.070)(3.5)}{0.047}\approx5.21\,\frac{m}{s^{2}}

c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is Q=\frac{V}{t}, so we can write:

A_{1}v_{1}=\frac{V}{t}, solving for V:

V=A_{1}v_{1}t=(0.070m^{2})(3.5\frac{m}{s})(3600s)=882\,m^{3}

3 0
4 years ago
What is the mass of a dog that weighs 382 N?(unit=kg)
tino4ka555 [31]

Answer:

38.77 kg

Explanation:

The weight of an object is given by:

Weight = mg,  g = acceleration due to gravity ( 9.8 m/s square)

and m is the mass.

So, in this case:

Weight of dog is 382 N, so, by putting the values of weight and g into the equation we will get the mass of dog.

382 = mass multiply with 9.8

so, the mass of the dog will be 38.77 kg

4 0
4 years ago
PLEASEHELP THANK YOU SM
garri49 [273]

Answer:

I belive it would be the first answer choice.

Explanation:

When the Mass is lower, the ball moves faster so it would have more kintetic energy

7 0
3 years ago
Read 2 more answers
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