Determine the factors of x2 − 12x − 20.
2 answers:
Answer:
Step-by-step explanation:
x² − 12x − 20 = 0
a = 1; b = (-12); c = (-20)
b²-4ac = (-12)² - 4 * 1 * (-20) = 144 + 80 = 224
√b²-4ac = √ 224 = √ 2*2*2*2*2*7 = 2*2*√(2*7) = 4√14
delta = -b ± √b²-4ac / 2a
= <u>-(-12) ± 4√14 </u>
2 * 1
= (12 ± 4√14)/2
= 2 ( 6 ± 2√14) / 2
= 6 ± 2√14
x = 6 + 2√14; x = 6 - 2√14
Answer:
(x-10)(x-2)
Formula:
a^{2} - b^{2} = (a-b)(a+b)
Explanation:
(x-6)^2-4^2
Then we can simplify to, (x-6-4)(x-6+4)
Which comes to your answer, (x-10)(x-2)
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