Answer:
The temperature is 42.5 °C
Explanation:
We apply the Law of Ideal Gases to solve this:
P . V = n . R . T
First, we convert the bar into atm, so we make a rule of three.
1.013 bar is 1 atm
1.3 bar is (1.3 . 1) /1.013 = 1.28 atm
1.28atm . 15L = n . 0.082 . T
We must convert the mass to moles ( mass / molar mass)
20 g / 30 g / mol = 0.666 moles
1.28atm . 15L = 0.666 mol . 0.082 . T
(1.28 atm . 15L) / (0.666 mol . 0.082) = T
315.5 K = T
As this is absolute temperature we must convert to °C
315.5 K - 273= 42.5 °C
Answer:
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Explanation:
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Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant =
T = temperature in Kelvins
K = equilibrium constant
We have :

1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)

The free energy change for the reaction at 37.0°C is -8.741 kJ.