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blondinia [14]
3 years ago
10

The sum of the first three terms of an arithmetic sequence is 108, and the sum of the next three terms is 183. what is the value

of the 11th term
Mathematics
1 answer:
qaws [65]3 years ago
4 0
The key is to find the first term a(1) and the difference d.

in an arithmetic sequence, the nth term is the first term +(n-1)d
the firs three terms: a(1), a(1)+d, a(1)+2d
the next three terms: a(1)+3d, a(1)+4d, a(1)+5d,
a(1) + a(1)+d +a(1)+2d=108
a(1)+3d + a(1)+4d + a(1)+5d=183

subtract the first equation from the second equation: 9d=75, d=75/9=25/3
Plug d=25/3 in the first equation to find a(1): a(1)=83/3

the 11th term is: a(1)+(25/3)(11-1)=83/3 +250/3=111

Please double check my calculation. <span />
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Express the number .0957 as a percent rounded to the hundredth place. (please include the % symbol.)
Gemiola [76]
The answer would be 9.57%. You would move the decimal 2 places to the right and add the percent.<span />
4 0
3 years ago
Sam is baking 10 pies for a school bake sale. He uses 21 cups of apples for 6 pies. How many cups of apples will he need to make
sertanlavr [38]

Answer:

35

Step-by-step explanation:

6 pies = 21 cups of apples

1 pie =  3.5 cups of apples

10 pies = 35 cups of apples

7 0
3 years ago
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
3 years ago
Help me 7th grade math please
Stolb23 [73]

Answer: 13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

The 29.2 ounce bottle is better

Step-by-step explanation:

13.5 ounce bottle for $2.19

a 29.2 ounce bottle for $5.37

find the ratios

13.5/2.19 = $6.16 per unit

29.2/5.37 = $5.44 per unit

3 0
2 years ago
Simplify each algebraic expression by combing like terms 7x^2-5x+10x-8x^2
castortr0y [4]

Answer: -x^2 + 15x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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