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guapka [62]
3 years ago
5

When a body moves from point A to point B the distance travelled in 500 meters with in a given time of 0.6 hours and find out th

e velocity and acceleration in a body.
what is correct answer .​
Physics
1 answer:
Sav [38]3 years ago
6 0

Answer

Explanation:

Convert the time to seconds = 0.6 × 60 × 60

= 2160seconds

Velocity = distance ÷ time

Velocity = 500 ÷ 2160

Velocity = 0.23meters per seconds(m/s)

Acceleration = Velocity ÷ time

Acceleration = 0.23 ÷ 2160

Acceleration = 0.000106meters per seconds ²(m/s²)

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Find the current that flows in a silicon bar of 10-μm length having a 5-μm × 4-μm cross-section and having free-electron and hol
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The current flowing in silicon bar is 2.02 \times 10^-12 A.

<u>Explanation:</u>

Length of silicon bar, l = 10 μm = 0.001 cm

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μn = 1200 cm^2 / V s

μр = 500 cm^2 / V s

The total current flowing in the bar is the sum of the drift current due to the hole and the electrons.

J = Je + Jh

J = n qE μn + p qE μp

where, n and p are electron and hole densities.

J = Eq (n μn + p μp)

we know that E = V / l

So, J = (V / l) q (n μn + p μp)

     J = (1.6 \times 10^-19) / 0.001 (104 \times 1200 + 1016 \times 500)

     J = 1012480 \times 10^-16 A / m^2.

or

J = 1.01 \times 10^-9 A / m^2

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A is the area of bar, A = 20 μm = 0.002 cm

I = 1.01 \times 10^-9 \times 0.002 = 2.02 \times 10^-12

So, the current flowing in silicon bar is 2.02 \times 10^-12 A.  

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