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guapka [62]
2 years ago
5

When a body moves from point A to point B the distance travelled in 500 meters with in a given time of 0.6 hours and find out th

e velocity and acceleration in a body.
what is correct answer .​
Physics
1 answer:
Sav [38]2 years ago
6 0

Answer

Explanation:

Convert the time to seconds = 0.6 × 60 × 60

= 2160seconds

Velocity = distance ÷ time

Velocity = 500 ÷ 2160

Velocity = 0.23meters per seconds(m/s)

Acceleration = Velocity ÷ time

Acceleration = 0.23 ÷ 2160

Acceleration = 0.000106meters per seconds ²(m/s²)

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2 years ago
A 12.0 g bullet was fired horizontally into a 1 kg block of wood. The bullet initially had a speed of 250 m/s. The block of wood
LuckyWell [14K]

Answer:

The rise in height of combined block/bullet from its original position is 0.45m

Explanation:

Given;

mass of bullet, m₁ = 12 g = 0.012 kg

mass of block of wood, m₂ = 1 kg

initial speed of bullet, u₁ = 250 m/s.

initial speed of block of wood, u₂ = 0

From the principle of conservation of linear momentum, calculate the final speed of the combined block/bullet system.

m₁u₁ + m₂u₂ = v(m₁+m₂)

where;

v is the final speed of the combined block/bullet system.

0.012 x 250 + 0 = v (0.012 + 1)

3 = v (1.012)

v = 3/1.012

v = 2.96 m/s

From the principle of conservation of energy, calculate the rise in height of the block/bullet combined from its original position.

¹/₂mv² = mgh

¹/₂v² = gh

¹/₂ (2.96)² = (9.8)h

4.3808 = 9.8h

h = 4.3808/9.8

h = 0.45 m

Therefore, the rise in height of combined block/bullet from its original position is 0.45m

7 0
3 years ago
Read 2 more answers
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