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sergey [27]
3 years ago
12

6. What are the four chambers of the heart? A. atrium, artery, ventricle, vein B. artery, blood vessel, capillary, vein C. blood

, carbon dioxide, oxygen, and plasma D. right atrium, left atrium, right ventricle, left ventricle
Physics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

The answer is D. right atrium, left atrium, right ventricle, left ventricle

Explanation:

The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle.The right ventricle pumps the oxygen-poor blood to the lungs.The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle.The left ventricle pumps the oxygen-rich blood to the body.

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If the intensity level of one trombone is 70 dB, calculate a reasonable estimate for the intensity level of 76 trombones all pla
kogti [31]

Answer:

 β₂ = 88.8 dβ

Explanation:

The intensity of the sound is

        β = 10 log (I / I₀)

The sensitivity threshold (I₀) for humans is 1 10⁻¹² W / m²

       I = I₀  10^{\beta /10}

       I = 10⁻¹² 10^{70/10}  

       I = 1 10⁻⁵ W / m²

The total intensity for the 76 trombones is

         I_total = n I

         I_total = 76 1 10⁻⁵

         I_total = 76 10⁻⁵ W / m²

Let's find the sound level

       β₂ = 10 log (76 10⁻⁵ / 10⁻¹²)

       β₂ = 88.8 dβ

8 0
3 years ago
Whose definition of acids and bases emphasizes the role of protons
torisob [31]

Answer:

Bronsted Lowry

Explanation:

Acid is defined as a proton donor.

While base is a proton acceptor

What is an acid An acid

An acid is a substance that donates protons or accepts a pair of valence electrons to form a bond

What is a base?

A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

3 0
3 years ago
A series of pulses, each of amplitude 0.1m , is sent down a string that is attached to a post at one end. The pulses are reflect
sp2606 [1]

The net displacement at a point on the string where the pulses cross is 0.2 m.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the ends are free.

There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.

Now, since A = 0.1 m

Then, 2A = 2(0.1) = 0.2 m

As a result, the net displacement at the string's intersection of two pulses is 0.2 m.

The correct option is (c).

Learn more about amplitude here:

brainly.com/question/3613222

#SPJ4

4 0
2 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
True [87]

Answer:

The last one " They are equal and act in opposite directions"

Explanation:

Hope u got it right.

5 0
3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0
3 years ago
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