The major ionic species present in aqueous solution of sodium sulfate is
2 Na+ and SO4^2-
<u><em>explanation</em></u>
When electrolyte dissolve in water they dissociate into ions.
There are two type of electrolyte that is strong and weak electrolyte.
Sodium sulfate is a strong electrolyte and therefore it dissociate completely into ions as below
Na2So4 → 2 Na+ (aq) + So4^2- (aq)
pH of the Sr(OH)₂ solution : 12.6
<h3>Further explanation </h3>
pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
Sr (OH) ₂ solution is a base with valence 2, so we determine the pOH from the OH ion concentration - which is expressed by pOH = - log [OH -]. After that we determine the pH value from the relationship:
[H⁺] [OH⁻] = Kw=10⁻¹⁴
pH + pOH = 14
Sr(OH)₂⇒Sr²⁺+2OH⁻
From equation [Sr(OH)₂] : [OH⁻]=1 : 2, so [OH⁻]=
My answer would be B, Hope i helped u??
Answer:
2.0 l
Explanation:
When for 20 °C volume is 1 l then for 40°C is going to be 2 l
20-------1
40-------x
x=(40*1):20