Question

The length of a square is increased by a 5th so that its new area is 44 cm2 more than the original value. find the difference in perimeter of two shapes.

Answer 1

Let the original length be x, then the new length is 6/5x
x^2 + 44 = (6/5 x)^2
x^2 + 44 = 36/25 x^2
36/25 x^2 - x^2 = 44
11/25 x^2 = 44
x^2 = (44 x 25)/11 = 100
x = 10 cm.
Therefore, original length is 10cm and new length is 1.2 x 10 = 12 cm.

Perimeter of a square = 4l
Therefore, difference in perimeter = 4(12) - 4(10) = 48 - 40 = 8 cm.