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agasfer [191]
3 years ago
15

If you measured 25 g jelly beans and 25 g of gumdrops, the number of jellybeans would be

Physics
2 answers:
Ivahew [28]3 years ago
8 0

B. More than the gum drops

KengaRu [80]3 years ago
7 0

The number of jellybeans would be B.more than the gumdrops.

Please rate brainliest.

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4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

=\frac{20}{5}

= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

W^t = \frac{63025*H}{\frac{n_pd}{2}}

W^t = \frac{63025*30}{2000*\frac{4}{2}}

W^t = 472.69 lbf

Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

\sigma = 15073.07 psi

\sigma = 15.07 ksi

∴ The estimate of the bending stress = 15.07 ksi

4 0
3 years ago
Read 2 more answers
Carter found the rock shown in the picture below near a river ​
noname [10]

Answer:

there's no picture

Explanation:

and what would the question be anyways?

4 0
3 years ago
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Power describes the ______ of the work that is being done.
Grace [21]
Power is the rate at which work is being done.
5 0
3 years ago
Before scientists come up with a scientific question, what do they have to do first?
Mademuasel [1]
Scientist would check what other scientists have said before they come up with their own scientific question. That way they can record the results from the others and compare them with their own findings when they conduct their own experiments and record the findings.
8 0
3 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a –80-nC charge at x = –4 m on
olchik [2.2K]

Answer:

The answer is + 4.8V

Explanation:

The electric potential is

         V = k ∑ q_{i} / r_{i}

We apply this expression to our case with three charges

        V = k (q₁ / r₁ + q₂ / r₂ + q₃ / r₃)

The distance is

        R = √((x-x₀)² + (y-y₀)²+ (z-z₀)²)

Let's find the distances

q₁ = 50 10⁻⁹ C

r₁ = √ ((8-0)² + (0-6)²)

r₁ = 10m

q₂ = -80 10⁻⁹ C

r₂ = √ ((8 + 4)²

r₂ = 12m

q₃ = 70 10⁻⁹ C

r₃ = √ ((8-0)²+ (0 + 6)²)

r₃ = 10 m

We calculate the potential

    V = 8.99 10⁸ 10⁻⁹ (50/10 -80/12 +70/10)

    V = 4.795 V

The answer is + 4.8V

5 0
3 years ago
Read 2 more answers
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