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Effectus [21]
4 years ago
8

Explain why the term Nano is used to describe nanotechnology​

Physics
1 answer:
Volgvan4 years ago
5 0

Answer:

Nanotechnology means working with materials at the scale of one billionth of a metre.

Explanation:

The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.

I hope this helps :)

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TRUE OR FALSE The time period of a simple pendulum does not depend upon mass, but depends, but depends on the size of the bob, b
Dimas [21]

Time period depends on the length of the pendulum and the force of gravity.

<h3>On what things time period depends?</h3>

The time period of a simple pendulum does not depend on mass and material of the bob. It depends on the length of the pendulum and the force of gravity because more length of the pendulum leads to more time to complete one cycle.

So we can conclude that time period depends on the length of the pendulum and the force of gravity.

Learn more about time here: brainly.com/question/2854969

#SPJ1

3 0
2 years ago
An ideal horizontal spring-mass system has a mass of 1.0 kg and a spring with constant 78 N/m. It oscillates with a period of 0.
steposvetlana [31]

Answer:

T = 0.71 seconds

Explanation:

Given data:

mass m = 1Kg, spring constant K = 78 N/m, time period of oscillation T = 0.71 seconds.

We have to calculate time period when this same spring-mass system oscillates vertically.

As we know

T = 2\pi \sqrt{\frac{m}{K} }

This relation of time period is true under every orientation of the spring-mass system, whether horizontal, vertical, angled or inclined. Therefore, time period of the same spring-mass system oscillating  vertically too remains the same.

Therefore, T = 0.71 seconds

6 0
3 years ago
Can someone help me?​
Leviafan [203]

Car X traveled 3d distance in t time.  Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t,  the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

V_y.t = \frac{2d}{t} .t = 2d

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0
3 years ago
Your ear is capable of differentiating sounds that arrive at the ear just 1.00 ms apart. What is the minimum distance (in cm) be
kenny6666 [7]

Answer:

34.3cm

Explanation:

Attached is the full solution

8 0
4 years ago
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this
Ne4ueva [31]

Answer:

In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.

Explanation:

Horizontal reach formula for projectiles tells us

d=\frac{v_i^2\sin(2\theta)}{g},

where v_i is the initial velocity and \theta the angle above the horizontal.

Since for both shots the reach must be the same, we have

\frac{v_i^2\sin(2\theta_1)}{g}=\frac{v_i^2\sin(2\theta_2)}{g}\\\sin(2\theta_1)=\sin(2\theta_2)\\\theta_2=\frac{1}{2}\arcsin(\sin(2\theta_1))=\frac{1}{2}\arcsin(\sin(2\times 72\deg))=\mathbf{18\deg}.

8 0
4 years ago
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