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3 years ago

The loudness of a sound is determined by the __________, or height, of the sound wave.

Physics

2 answers:

Fittoniya [83]3 years ago

6 0

just took the quiz

balandron [24]3 years ago

5 0

C. amplitude....................

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A wheel that was initially spinning is accelerated at a constant angular acceleration of 5.0 rad/s^2. After 8.0 s, the wheel is

notka56 [123]

Answer:

a) Initial angular speed = 30 rad/s

b) Final angular speed = 70 rad/s

Explanation:

a) We have equation of motion s = ut + 0.5at²

Here s = 400 radians

t = 8 s

a = 5 rad/s²

Substituting

400 = u x 8 + 0.5 x 5 x 8²

u = 30 rad/s

Initial angular speed = 30 rad/s

b) We have equation of motion v = u + at

Here u = 30 rad/s

t = 8 s

a = 5 rad/s²

Substituting

v = 30 + 5 x 8 = 70 rad/s

Final angular speed = 70 rad/s

8 0

3 years ago

What happens when stress builds up at faults?

Harlamova29_29 [7]

Answer:

The answer is D because when the faults move that is the tectonic plates moving. So earth quakes will be forming when the fault moves.

Explanation:

3 0

3 years ago

Read 2 more answers

You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity

Anarel [89]

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

W = (10 N) (-1.0 m) = -10 J

5 0

3 years ago

You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1

drek231 [11]

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

The given parameters;

Mass of the pendulum, = M
Length of the pendulum, = L
Initial angular speed, $\omega _i$ = 1 rad/s

The moment of inertia of the rod about the end is given as;

$I_i = \frac{1}{3} ML^2$

The moment of inertia of the rod between the middle and the end is calculated as;

$I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}$

Apply the principle of conservation of angular momentum as shown below;

$I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f$

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

Learn more about moment of inertia of uniform rod here: brainly.com/question/15648129

3 0

3 years ago

Please help me , thank you

mash [69]

Answer:

Since the reading wasn't specified, it would be most likely A

Explanation:

A is the most similar to a protoplanetary disk, so it'd be A most likely

5 0

3 years ago