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frosja888 [35]
3 years ago
8

The loudness of a sound is determined by the __________, or height, of the sound wave.

Physics
2 answers:
Fittoniya [83]3 years ago
6 0

c

just took the quiz

balandron [24]3 years ago
5 0

C.    amplitude....................


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One of the largest barometers ever built was an oil-filled barometer constructed in Leicester, England in 1991. The oil had a he
ZanzabumX [31]

Answer:

ρ = 830.32 kg/m³

Explanation:

Given that

Oil head = 12.2 m

h= 12.2 m

Pressure P = 1.013 x 10⁵ Pa

Lets take density of the liquid =ρ

The pressure due to liquid P given as

P = ρ g h

Now by putting the all values in the above equation

1.013 x 10⁵ Pa = ρ x 10 x 12.2                 ( take g =10 m/s²)

ρ = 830.32 kg/m³

Therefore the density of oil is 830.32  kg/m³

5 0
3 years ago
Which of the following is a small star that has reached the end of its stellar evolution?
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D.) White Dwarf

It is the smallest star whose mass is approximately equal or greater than 1.4M
Here, M = mass of the Sun.

Hope this helps!
3 0
3 years ago
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What is the best reason for a student to remove a dangling bracelet when heating test tubes of acidic solutions in a hot water
soldi70 [24.7K]

Answer:

c

Explanation:

this equestion is about the safety

4 0
3 years ago
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I need help and please hurry.
anyanavicka [17]
Hi, time is independent variable. It's stands alone and isn't change by anything.
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5 0
3 years ago
A large solar panel on a spacecraft in Earth orbit produces 1.0 kW of power when the panel is turned toward the sun. What power
Mandarinka [93]

Answer:

e*P_s = 11 W

Explanation:

Given:

- e*P = 1.0 KW

- r_s = 9.5*r_e

- e is the efficiency of the panels

Find:

What power would the solar cell produce if the spacecraft were in orbit around Saturn

Solution:

- We use the relation between the intensity I and distance of light:

                                  I_1 / I_2 = ( r_2 / r_1 ) ^2

- The intensity of sun light at Saturn's orbit can be expressed as:

                                  I_s = I_e * ( r_e / r_s ) ^2

                                  I_s = ( 1.0 KW / e*a) * ( 1 / 9.5 )^2

                                  I_s = 11 W / e*a

- We know that P = I*a, hence we have:

                                  P_s = I_s*a

                                  P_s = 11 W / e

Hence,                       e*P_s = 11 W

3 0
2 years ago
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