Answer:
Explanation:
We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.
The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.
- ΔT= final temperature - initial temperature
The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.
- ΔT= 92.1 °C - 12.5 °C= 79.6°C
Now we know three variables and can substitute them into the formula,
- m= 112.5 g
- c= 4.184 J/g °C
- ΔT= 79.6 °C
Multiply the first 2 numbers. Note the units of grams cancel.
Multiply again. This time the units of degrees Celsius cancel.
37, 467.72 Joules of heat are absorbed by the sample fo water.
Boyle's law gives the relationship between pressure of a gas and volume of gas.
It states that at constant temperature, pressure of gas is inversely proportional to volume of gas.PV = k
where P - pressure V- volume and k - constant
P1V1 = P2V2
since the gas occupies the volume of the container, volume of gas is taken as volume of container.
100kPa x 5.0 L = 50 kPa x V
V = 10.0 L
Answer is C.
C. a scientific approach to answering questions
Answer:
22km
Explanation:
Las velocidades de los móviles nos van a definir cuánta distancia recorren por unidad de tiempo. Para resolver este problema debemos hallar la distancia recorrida en una hora por cada vehículo (Porque de las 12 horas a las 13 solo hay una hora)
Un móvil está recorriendo 50km/h. En una hora recorrerá: 50km
El otro móvil recorre 20m/s. En km/h:
20m/s * (3600s / h) = 72000m/h * (1km / 1000m) = 72km/h. El móvil recorrerá, en una hora, 72km
<em>1h = 3600s; 1km = 1000m</em>
La distancia que los separa es de:
72km - 50km =
22km
