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Nesterboy [21]
3 years ago
8

If a solid has a density of 4.0 g/cm^3, what volume of the solid has a mass of 24 g? Show work.

Chemistry
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

<h2>Volume = 6 cm³</h2>

Explanation:

Density of a substance is given by

Density =  \frac{mass}{volume}

From the question

Density = 4.0 g/cm³

mass = 24g

Substitute the values into the above formula and solve for the volume

That's

4 =  \frac{24}{v}  \\4v = 24

Divide both sides by 4

v = 6

We have the final answer as

<h3>Volume = 6 cm³</h3>

Hope this helps you

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2Ag + S --&gt; Ag2S would be classified as a(n) _____________ reaction.
yaroslaw [1]

Answer:

its 2 parts creating a group which would be combustion

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3 years ago
Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
5 0
3 years ago
What is a solute?
olya-2409 [2.1K]

Answer:

C. The substance that is dissolved in another substance

Explanation:

a solute is a substance dissolved in another substance, known as a solvent

5 0
2 years ago
9. How does the electron configuration of an ion of
madreJ [45]

Explanation:

Group 1A consist of metals and group. 2A consist of non metals . group1A elements can become stable by donating 1 electron in the same way the elements of group 7A also becomes stable by gaining one electron . So due to being so close to being a inert gas element it is compared to the nearest noble gas.

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2 years ago
Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed
masya89 [10]

(A) 7.28\cdot 10^{-10} m

The De Broglie wavelength of an electron is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

v=1.00\cdot 10^6 m/s

and its mass is

m=9.11\cdot 10^{-31} kg

So, its momentum is

p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s

And substituting into (1), we find its De Broglie wavelength

\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m

(B) 1.16\cdot 10^{-34}m

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s

And so, the De Broglie wavelength of the ball is given by

\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m

(C) 9.02\cdot 10^{-9}m

The location of the first intensity minima is given by

y=\frac{L\lambda}{a}

where in this case we have

y=0.492 cm = 4.92\cdot 10^{-3} m

L = 1.091 is the distance between the detector and the slit

a=2.00\mu m=2.00\cdot 10^{-6}m is the width of the slit

Solving the formula for \lambda, we find the wavelength of the electrons in the beam:

\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m

(D) 7.35\cdot 10^{-26}kg m/s

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

p=\frac{h}{\lambda}

where here we have

\lambda=9.02\cdot 10^{-9}m is the wavelength

Substituting into the formula, we find

p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s

7 0
3 years ago
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