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Nesterboy [21]
3 years ago
8

If a solid has a density of 4.0 g/cm^3, what volume of the solid has a mass of 24 g? Show work.

Chemistry
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

<h2>Volume = 6 cm³</h2>

Explanation:

Density of a substance is given by

Density =  \frac{mass}{volume}

From the question

Density = 4.0 g/cm³

mass = 24g

Substitute the values into the above formula and solve for the volume

That's

4 =  \frac{24}{v}  \\4v = 24

Divide both sides by 4

v = 6

We have the final answer as

<h3>Volume = 6 cm³</h3>

Hope this helps you

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Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological
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The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, t_\frac{1}{2}, the age, t, and amount remaining, A_{r}, of a radioactive material are related by the formula below:

  • t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}

Half-life of carbon-14 = 6000 years

For the Egyptian papyrus with 63% of its original carbon-14 atoms:t = \frac{6000*0.63}{-0.63} = 4000\:years

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

t = \frac{6000*0.22}{-0.63} = 13106.5\:years

For the Mayan headdress with 79% of its original carbon-14 atoms:

t = \frac{6000*0.79}{-0.63} = 2040\:years

Neanderthal skull with 3% of its original carbon-14 atoms:

t = \frac{6000*0.03}{-0.63} = 30353\:years

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

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