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ivolga24 [154]
2 years ago
5

Compared to the nucleus 5626fe, what is the density of the nucleus 112 48cd?

Chemistry
1 answer:
tia_tia [17]2 years ago
8 0

For a comparison of the nucleus 5626fe, the density of the nucleus 112 48cd is mathematically given as the same.

n(Cd) / n(Fe)=1

<h3>What is the density of the nucleus 112 48cd?</h3>

Generally, the equation for the density  is mathematically given as

d=\frac{A}{4/3}\piR^3

Therefore

n(Cd) / n(Fe) = [A (Cd) / (A Fe) ] * [ R (Fe) / R (Cd)]^3

n(Cd) / n(Fe)= (112 / 56 ) * (1/1.26)3

n(Cd) / n(Fe)=1

In conclusion, The ratio of n(Cd) = n(Fe) is 1, hence same

Read more about density

brainly.com/question/14010194

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