Answer:
21 L
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
Answer:
-138.9 kJ/mol
Explanation:
Step 1: Convert 235.8°C to the Kelvin scale
We will use the following expression.
K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K
Step 2: Calculate the standard enthalpy of reaction (ΔH°)
We will use the following expression.
ΔG° = ΔH° - T.ΔS°
ΔH° = ΔG° / T.ΔS°
ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K
ΔH° = -3.583 kJ (for 1 mole of balanced reaction)
Step 3: Convert -9.9°C to the Kelvin scale
K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K
Step 4: Calculate ΔG° at 263.3 K
ΔG° = ΔH° - T.ΔS°
ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K
ΔG° = -138.9 kJ/mol
Answer:
Explanation:
There are key organs and system that assist in ensuring the body maintains homeostasis in the case of water-salt balance.
The excretory system: When one sweats, a lot of water content of the blood can drop (this is what causes the individual to be thirsty). In order to maintain a certain water-salt balance, the excretory system passes some salt out of the body in the form of urine (this is the reason the urine is usually yellowish but small in volume during the summer).
Endocrine system: When water content of the blood drops, vasopressin (also called antidiuretic hormone) is released into the bloodstream stimulating the kidneys to conserve water and release less urine (as said earlier). However, if the body is hydrated, less vasopressin is released and more water is passed in the urine.
