Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate
in order to prepare a 0.452 m solution
Explanation:
Molality : It is defined as the number of moles of solute present per kg of solvent
Formula used :

where,
n= moles of solute
Moles of
= weight of the solvent in g = ?


Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate
in order to prepare a 0.452 m solution
That is correct c
Explanation
Conductivity, malleability, and high melting points. Hope this helps :)
Answer:
The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²
Explanation:
The given parameters is as follows;
The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g
The required information = The number of formula units of potassium chloride (KCl)
The Molar Mass of KCl = 74.5513 g/mol

Therefore, we have;

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units
Therefore;
0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units
From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.
The answer to your question is,
B) CaCl2
-Mabel <3