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3 years ago

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What can you tell about the location of the Sun from this illustration of the Milky Way? A) It is outside of the Milky Way. B) I

t is near an outer arm of the Milky Way. C) It is on the right side of the Milky Way. D) It is within the Central Bulge of the Milky Way. Hint

1 answer:

MakcuM [25]3 years ago

7 0

It is within the central bulge

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Consider the compound hydroxyapatite, Ca10(PO4)6(OH)2. Name each ion present, give the charge of each ion and show that the form

emmainna [20.7K]

Ca₁₀(PO₄)₆(OH)₂ or Ca(OH)₂·3Ca₃(PO₄)₂

PO₄³⁻   phosphate ion
OH⁻   oxyhydroxide ion
Ca²⁺   calcium ion

10*(+2) + 6*(-3) + 2*(-1) = 0
10Ca²⁺ 6PO₄³⁻ 2OH⁻

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2 years ago

Scientists believe that ancient bacteria represents the first evidence of life on Earth. Which of these best describes the proce

Goryan [66]

I would probably say transformation of virus like molecules

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3 years ago

How many particles would be found in a 1.224 g sample of K2O

lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0

3 years ago

Read 2 more answers

Why would the federal government and city government find it necessary regulate water standard?

Helga [31]

They do this so that when you drink it or use it the contaminates that used to be in it dont make you sick

4 0

3 years ago

In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)

lyudmila [28]

Answer : The mass of $NaBr$ is, 295.323 grams

Solution :

First we have to calculate the moles of $NaNO_3$ .

$\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles$

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

$Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)$

From the balanced reaction we conclude that

As, 2 moles of $NaNO_3$ react with 2 moles of $NaBr$

So, 2.87 moles of $NaNO_3$ react with 2.87 moles of $NaBr$

Now we have to calculate the mass of NaBr.

$\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr$

$\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g$

Therefore, the mass mass of $NaBr$ is, 295.323 grams

7 0

2 years ago