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Annette [7]
3 years ago
15

What can you tell about the location of the Sun from this illustration of the Milky Way? A) It is outside of the Milky Way. B) I

t is near an outer arm of the Milky Way. C) It is on the right side of the Milky Way. D) It is within the Central Bulge of the Milky Way. Hint
Chemistry
1 answer:
MakcuM [25]3 years ago
7 0
It is within the central bulge
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Plz help me with these electron dot structures!
abruzzese [7]

Answer:

Explanation:

chlorine

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sulfur dioxide

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6 0
3 years ago
a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
4 years ago
28.6 hectoliter = centiliter
Lapatulllka [165]
<h2>Answer:</h2><h2>28000 centiliter</h2><h2>Good luck </h2>

7 0
3 years ago
Read 2 more answers
CAN ANYONE SHARE 10 MEMES AND BAG THE BRAINLISST
Semmy [17]
*clink* a toast *clink* a toast *clink* a toast *clink* *clink*

5 0
3 years ago
Read 2 more answers
What is the relationship between the concentration of particles in a solution and the solution’s vapor pressure? As solute conce
kap26 [50]

Answer:

As solute concentration increases, vapor pressure decreases.  

Step-by-step explanation:

As solute concentration increases, the number of solute particles at the surface of the solution increases, so the number of <em>solvent </em>particles at the surface <em>decreases</em>.

Since there are fewer solvent particles available to evaporate from the surface, the vapour pressure decreases.

C. and D. are <em>wrong</em>. The vapour pressure depends <em>only</em> on the number of particles. It does not depend on the nature of the particles.

5 0
3 years ago
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