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Marysya12 [62]
3 years ago
5

On a distance vs time graph, what does the line of an object at constantspeed look like?​

Physics
1 answer:
9966 [12]3 years ago
4 0

Answer: Diagonal going up

Explanation:

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calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared usin
Lynna [10]

Answer:

minimum number of photon is 4.05 × 10^{7}

Explanation:

given data

energy = 50 keV = 50 × 10^{3} eV =  50 × 10^{3} × 1.602× 10^{-19}  J

thickness = 10^-3

contrast = 1%

to find out

number of incident photons

solution

we know here equation that is

E  = n  × h  × ν   .......................1

put here all these value

50 × 10^{3} = n × 6.6× 10^{-34} × c/ 1× 10^{-3}

50 × 10^{3} × 1.602× 10^{-19}  = n × 6.6× 10^{-34} ×( 3 × 10^{8} / 1× 10^{-3})

solve it and find n

n = 4.05 × 10^{7}

so here minimum number of photon is 4.05 × 10^{7}

3 0
3 years ago
A gas sample enclosed in a rigid metal container at room temperature (20.0∘C) has an absolute pressure p1. The container is imme
True [87]

Answer:

it is 60.0° C

Explanation:

that is the new pressure p2

4 0
3 years ago
Suppose you have a 115 kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood sur
alexdok [17]

Answer:

maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N

Explanation:

Given data:

mass m= 115 kg

coefficient of friction μ =0.5

according to newton law of motion the net force acted on body is given by

F_{net}=ma=F_{max}- F_{f}

here the body is in rest ,

F_{net}=0\\\Rightarrow F_{max}=F_{f}\\\text{frriction force}  F_{f} = \mu\times N\\

N= it is the normal reaction force

N= mg = 115×9.81

therefore,

F_{f} = 0.5\times115\times9.81 = 564.075 N = F_{max}

4 0
3 years ago
Write down your definition of work in the space below: ​
skelet666 [1.2K]

Answer:

Work is the energy transferred to or from an object via the application of force along a displacement.

5 0
3 years ago
Read 2 more answers
A straight line with a negative slope on a velocity-time graph indicates which of the following?
podryga [215]

Answer:

A

Explanation:

Straight line with a negative slope

On a velocity_time graph

5 0
3 years ago
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